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goblinko [34]
3 years ago
8

How many liters of pure water should be mixed with 18 liters of a12% saline solution to make a saline solution that is 3% salt?

Mathematics
1 answer:
Volgvan3 years ago
3 0

Answer: .42857 liters of pure water


Step-by-step explanation:2.4 = .7w + 2.1

2.4 - 2.1 = .7w

.3 = .7w

w = .3%2F.7


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Drag the tiles to the boxes to form correct pairs. Match each term to its definition
Illusion [34]

Answer:

Step-by-step explanation:

axiom goes with a given definition assumed to be true

theorem goes with a logical argument showing that a theorem is true

proof is a statement that requires proof

3 0
3 years ago
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The Software Company earned 2,247,852,199 dollars last year. This year they earned 3,000,962,245 dollars. Which is the best esti
RSB [31]

You know the following information:

1. The amount of money (in dollars) earned last year was:

2,247,852,199

2. The amount of money (in dollars) earned this year, is:

3,000,962,245

Then, to estimate the sum (the total amount of money the Software Company earned in those two years, you can round the numbers to the nearest billion.

Having:

2,247,852,199

You need to look at the digit located in the Hundred millions place. Notice that this is:

2

Then, since:

2

You need can't round up. Then:

2,247,852,199\approx2,000,000,000

Now, having:

3,000,962,245

You can identify that the digit in the Hundred millions place is

0

Therefore:

3,000,962,245\approx3,000,000,000

Now you can add the numbers rounded:

2,000,000,000+3,000,000,000=5,000,000,000

Hence, the answer is: Option B.

5 0
1 year ago
What is 2(2x+1) equivalent to
Nostrana [21]
2(2x+1)= (2 x 2x) + (2 x 1) = 4x + 2
6 0
3 years ago
Read 2 more answers
The sum of three integers is 12
Liula [17]

The three integers are 5,17 and -10

Step-by-step explanation:

Let x, y and z be three integers then

x+y+z=12 \ \ \Eqn\ 1

'The sum of the first and second integers exceeds the third by 32'

x+y=z+32\ \ \ \ Eqn\ 2

The third integer is 15  less than the first.

z=x-15\ \ \ \ Eqn\ 3

From Eqn 2:

x+y=z + 32\\x+y-z=32

Subtracting Eqn 1 from eqn 2

x+y-z-(x+y+z)=32-12\\x+y-z-x-y-z=20\\-2z=20

Dividing both sides by -2

\frac{-2z}{-2}=\frac{20}{-2}\\z=-10

Putting z=-10 in Eqn 3

z=x-15\\-10=x-15\\x=15-10\\x=5

Putting x=5 and z=-10 in Eqn 1

x+y+z=12\\5+y-10=12\\y-5=12\\y=12+5\\y=17\\

Hence,

The three integers are 5,17 and -10

Keywords: Linear Equations, Variables

Learn more about linear equations at:

  • brainly.com/question/13219835
  • brainly.com/question/1836777

#LearnwithBrainly

3 0
3 years ago
Read 2 more answers
Can someone please help with me 14? I want to know what I did wrong. I got 1 point taken off and I don’t know how to fix it
r-ruslan [8.4K]

Answer:

2x

Step-by-step explanation:

log4(16^x)

log4(4²^x)

log4(4^2x)

2x log4(4)

2x

You completely left out the x, approach is fine though

8 0
3 years ago
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