You can use the Pythagorean Theorem to find the length of the third side AB (Identified as "x" in the figure attached in the problem), which says that in a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the legs:
a² = b²+c²
As we can see the figure, the triangle does not have an angle of 90°, but it can be divided into two equal parts, leaving two triangles with a right angle. We already have the values of the hypotenuse and a leg in triangle "A" , so we can find the value of the other leg:
b = √(a²-c²) b = √(10²-4²) b = 9.16
With these values, we can find the hypotenuse in the triangle "B": x = √b²+c² x = √(9.16)²+(4)² x = 10
1.) C
2.) A
3.) B
4.) C
5.) idk
6.) A
7a.) non proportional because the line does not pass through the origin (0,0)
7b.) The slope is -2x
7c.) The y-intercept of the line is -3.
7d.) The equation of the line is y = -2x - 3
Answer: -12
Step-by-step explanation:
You find values of 28 that add to -11! in this case thats -7 and -4. after that just plug in (x-7)(x-4)=0 so: x=4, x=7
Overall dimensions of the page in order to maximize the printing area is page should be 11 inches wide and 10 inches long .
<u>Step-by-step explanation:</u>
We have , A page should have perimeter of 42 inches. The printing area within the page would be determined by top and bottom margins of 1 inch from each side, and the left and right margins of 1.5 inches from each side. let's assume width of the page be x inches and its length be y inches So,
Perimeter = 42 inches
⇒ 
width of printed area = x-3 & length of printed area = y-2:
area = 
Let's find 
:
= 
, for area to be maximum = 0
⇒ 
And ,
∴ Overall dimensions of the page in order to maximize the printing area is page should be 11 inches wide and 10 inches long .
