If DE ⊥ EF, then ∠DEF is a right angle, provide a counter example if false... help??

20p to whoever helps! (OwO)

Anni [7]

Answer:

See below

Step-by-step explanation:

4 more than 3: 3 + 4 = 7

5 out of 9: 5/9

the sum of 6 and 8: 6 + 8 = 14

10 less than 14: 14 - 10 = 4

the product of 3 and 4: 3 * 4 = 12

the ratio of 2 to 3: 2/3

10 decreased by 8: 10 - 8 = 2

the quotient of 23 and 25: 23/23

3 increased by 33: 3 + 33 = 36

50% of 32: 50% * 32 = 0.5 * 32 = 16

4 0

2 years ago

Read 2 more answers

Ahhh hi pls help <br> f(x)=-2x^2+3

nikklg [1K]

Answer:

Step-by-step explanation:

F(x) is another name for y

If you make a table of values, you can plot the coordinates of this quadratic equation.

When "x" is 0, y is 3

7 0

3 years ago

Bella went to a carnival and played a game that involved throwing a basketball into a moving basket. She had two minutes to make

GalinKa [24]

Answer:

6

Step-by-step explanation:

12*2=24 24/4=6

8 0

3 years ago

The sum of 2 fractions is 5/6. Their difference is 1/2. Their least common denominator is 6. The denominator of one is twice the

valentinak56 [21]

Answer:

Step-by-step explanation:

Alright, lets get started.

Suppose the first fraction is : $\frac{a}{b}$

Suppose the second fraction is : $\frac{c}{d}$

The sum of both fraction is given as : $\frac{5}{6}$

$\frac{a}{b}+\frac{c}{d}=\frac{5}{6}$ .......................equation (1)

The difference of both fraction is given as : $\frac{1}{2}$

$\frac{a}{b}-\frac{c}{d}=\frac{1}{2}$ .........................equation (2)

Adding equation (1) and equation (2)

$\frac{c}{d} \ will \ be \ cancelled$

$\frac{2a}{b}=\frac{5}{6}+\frac{1}{2}$

making common denominator

$\frac{2a}{b}=\frac{5}{6}+ \frac{3}{6}$

$\frac{2a}{b}=\frac{8}{6}$

Hence,

$\frac{a}{b}=\frac{2}{3}$

Plugging the value of $\frac{a}{b}$ in equation (1)

$\frac{2}{3}+\frac{c}{d}=\frac{5}{6}$

Subtracting $\frac{2}{3}$ in both sides

$\frac{c}{d}=\frac{5}{6}-\frac{2}{3}$

$\frac{c}{d}=\frac{1}{6}$

Hence both fractions are $\frac{2}{3} \ and \ \frac{1}{6}$ ...................Answer

Hope it will help :)

7 0

2 years ago

The normal temperature range for Yuma, AZ on January 11 is at least 48 degrees but no higher than 64 degrees Fahrenheit. Which i

WITCHER [35]

Answer: Our required interval for temperature is $48\leq x\leq 64$

Step-by-step explanation:

Since we have given that

The normal temperature range for Yuma, on Janurary is atleast = 48 degrees

and the highest temperature on that day is no higher than 64 degrees.

Let the temperature in Yuma be 'x'.

So, we know that for atleast means it can 48 degrees or more, and no higher than means it should be equa to or less than 64 degrees.

Mathematically, it is expressed as

$48\leq x\leq 64$

Hence, our required interval for temperature is $48\leq x\leq 64$

7 0

2 years ago