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Alenkasestr [34]
2 years ago
10

When x = 4 and y = 3, find the value of:

Mathematics
1 answer:
vichka [17]2 years ago
8 0

Answer:

a-8x+21y-10=19

b-3(x-6y)=6

c-(15-12)=4

Step-by-step explanation:

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What is the smallest Square number using 5 roman numerals?
In-s [12.5K]

Answer:

The answer is "1"

Step-by-step explanation:

Let 5 roman numbers are:

\to I=1\\\\\to II=2\\\\\to III=3\\\\\to IV= 4\\\\\to V=5

There square values are as follows:

\to 1^2=1\\\\\to 2^2=4\\\\\to 3^2=6\\\\\to 4^2=16\\\\\to 5^2=25

The smallest square number is= 1.

3 0
3 years ago
A 50 foot ladder is placed at 30 feet away from the building in order to reach the 3rd floor of the building. How high is the 3r
Sonbull [250]
The correct answer should be 20 feet
5 0
4 years ago
The dog has gone 5/8 of the way across the yard. How much farther does it have to go to reach the gate?
tigry1 [53]
<span>Well if one assumes that the dog is starting at one side opposite the gate and is heading directly for it, then it has 3/8 of the yard to go. However since one cannot know where the dog has started his movement toward the gate then the answer would not be solvable without more information.</span>
7 0
4 years ago
Solve the problem by entering and solving an equation.
geniusboy [140]

Given : A rectangular picture frame has a perimeter of 52 inches. The height of the frame is 12 inches.

To Find : The width of the frame .

Solution : Let us take the width of the frame be x . So , we know the formula to find the perimeter of rectangle as ;

\boxed{\red{\bf Perimeter_{rectangle}=2(l+b)}}

Where , l is the length of the rectangle and b is the breadth of the rectangle .

⇒ Perimeter = 2 ( l + b ) .

⇒ 52 in. = 2 ( 12 + x ) in.

⇒ 52 in.= 24in. + 2x .

⇒ 2x =( 52 - 24 ) in

⇒ 2x = 28 in.

⇒ x = 28/2 in.

⇒ x = 14 in.

<u>Henc</u><u>e</u><u> the</u><u> </u><u>width</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>recta</u><u>ngle</u><u> </u><u>is</u><u> </u><u>1</u><u>4</u><u> </u><u>inches</u><u>.</u>

5 0
3 years ago
What is 9| - z/3| + 6 &lt; 30
Reil [10]
9|⁻¹/₃z| + 6 < 30
9|⁻¹/₃z| + 6 < ±30
9|⁻¹/₃z| + 6 < 30    or    9|⁻¹/₃z| + 6 > -30
9(¹/₃z) + 6 < 30    or    9(¹/₃z) + 6 > -30
     3z + 6 < 30       or       3z + 6 > -30
           - 6   - 6                       - 6     - 6
           3z < 24          or          3z > -24
            3      3                         3       3
             z < 8            or            z > -8

Solution Set: {z|z < 8 or z > -8} and (-∞, 8) or (-8, ∞)
4 0
3 years ago
Read 2 more answers
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