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2 years ago

Please answer these questions I will mark brainliest

Mathematics

1 answer:

igor_vitrenko [27]2 years ago

4 0

1. C

2. A

3. A

i’m pretty sure for 1,2. 3 i’m a little iffy but i think it’s A bc “homogenizing”

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There were 42 apples in each crate. 12 such crates of apples were delivered to a factory. 4 apples were rotten and had to be thr

algol [13]

Answer:

50 boxes

Step-by-step explanation:

first we can find how many apples there are

42*12=504

then subtract 4 of the rotten apples

504-4=500

then find how many boxes there can be

500/10=50

7 0

3 years ago

What is the area of the composite figure?

d1i1m1o1n [39]

100cm2 that is the answer I got

4 0

3 years ago

Show that <br>sinx/1+cosx=tanx/2

hammer [34]

Answer:

See proof below

Step-by-step explanation:

show that

sinx/1+cosx=tanx/2

From LHS

sinx/1+cosx

According to half angle

sinx = 2sinx/2 cosx/2

cosx = cos²x/2 - sin²x/2

cosx = cos²x/2 - (1- cos²x/2)

cosx = 2cos²x/2 - 1

cos x + 1 = 2cos²x/2

Substitute into the expression;

sinx/1+cosx

= (2sinx/2 cosx/2)/2cos²x/2

= sinx.2/cos x/2

Since tan x = sinx/cosx

Hence sinx/2/cos x/2 = tan x/2 (RHS)

This shows that sinx/1+cosx=tanx/2

7 0

2 years ago

Part 2. State what additional information is required in order to know that the triangles are congruent by ASA.

Helga [31]

<h3>Answer: Choice D. $\angle SQR \cong \angle XQR$ </h3>

The red angle markers show those two angles are congruent. That's one "A" of "ASA". The S refers to a congruent pair of sides. We don't have any tickmarks to indicate congruent pairs; however, we do know that QR = QR is a shared side that overlaps (reflexive theorem). So this is the "S" in "ASA".

The thing missing is the angle Q of the top triangle, and also of the bottom triangle as well. If we know those two angles are congruent, then we have enough info to use ASA. More specifically, if we know that $\angle SQR \cong \angle XQR$ , then we can use ASA.

One thing to notice is that the other answer choices involve side lengths and not angles. This implies that if A, B or C were one of the answers, then we would have something like SAS or SSS. But instead we want ASA. So we can immediately rule choices A,B, and C out.

7 0

2 years ago

Heights of 10-year-olds, regardless of gender, closely follow a normal distribution with a mean of 55 inches and a standard devi

Svetllana [295]

Answer:

Step-by-step explanation:

Given that Heights of 10-year-olds, regardless of gender, closely follow a normal distribution with a mean of 55 inches and a standard deviation of 6 inches.

If X is height then X is N(55,6)

Z score would be $\frac{x-55}{6}$