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Novosadov [1.4K]
3 years ago
12

Sandy is helping her uncle at this coffee shop. She observes that, when ordering coffee, 13 of customers select chocolate flavor

ing. To simulate the behavior of the next 5 customers, she lets the number 1 represent someone ordering chocolate, and she lets the numbers 2 or 3 represent someone ordering a different flavor. She writes the numbers 1, 2, and 3 on cards and mixes them up. Sandy then picks one card, records the result, and puts the card back. She does this process four more times to represent 5 customers and to complete 1 trial of the experiment. She repeats this experiment for a total of 10 trials. The results are recorded in the table. 12323 13123 22222 23111 11322 31112 23331 11231 32332 13111 Using this simulation, what is the probability that 3 or more of the next 5 customers will order chocolate? Enter your answer, as a fraction in simplified form, in the box.

Mathematics
2 answers:
valkas [14]3 years ago
6 0
The answer is 2/5 :)

Have A Good Day
 
Please stay in school

Dont do drugs... Heroin is bad for your body

Love you dudes <3
Brilliant_brown [7]3 years ago
4 0
I did the test....
See below for proof :)
~Rosy67

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8 0
2 years ago
A stadium has 55,000 seats. Seats sell for ​$28 in Section​ A, ​$16 in Section​ B, and ​$12 in Section C. The number of seats in
salantis [7]
A=number of seats in section A
B=number of seats in section B
C=number of seats in section C

We can suggest this system of equations:

A+B+C=55,000
A=B+C                                      ⇒A-B-C=0
28A+16B+12C=1,158,000

We solve this system of equations by Gauss Method.

1             1              1               55,000
1            -1            -1                         0
28         16           12          1,158,000 


1             1              1               55,000
0            -2             -2             -55,000                                    (R₂-R₁)
0           12             16           382,000                                    (28R₁-R₂) 


1            1                1              55,000
0           -2              -2             -55,000
0            0                4               52,000                                     (6R₂+R₃)

Therefore:

4C=52,000
C=52,000/4
C=13,000


-2B-2(13,000)=-55,000
-2B-26,000=-55,000
-2B=-55,000+26,000
-2B=-29,000
B=-29,000 / -2
B=14,500.

A + 14,500+13,000=55,000
A+27,500=55,000
A=55,000-27,500
A=27,500.

Answer: there are 27,500 seats in section A, 14,500 seats in section B and 13,000 seats in section C.
3 0
3 years ago
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