The pH of the weak acid is 3.21
Butyric acid is known as a weak acid, we need the concentration of [H+] formula of weak acid which is given by this equation :
![[H^{+}]=\sqrt{Ka . Ma}](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%3D%5Csqrt%7BKa%20.%20Ma%7D)
where [H+] is the concentration of ion H+, Ka is the weak acid ionization constant, and Ma is the acid concentration.
Since we know the concentration of H+, the pH can be calculated by using
pH = -log[H+]
From question above, we know that :
Ma = 0.0250M
Ka = 1.5 x 10¯⁵
By using the equation, we can determine the concentration of [H+]
[H+] = √(Ka . Ma)
[H+] = √(1.5 x 10¯⁵ . 0.0250)
[H+] = 6.12 x 10¯⁴ M
Substituting the value of [H+] to get the pH
pH = -log[H+]
pH = -log(6.12 x 10¯⁴)
pH = 3.21
Hence, the pH of the weak acid c3h7cooh is 3.21
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Answer:
X=35
Step-by-step explanation:
6X =45 SO ANSWER TO THE QUESTION IS 35
The resulting fractions is 14/15
<h3>Solving equations</h3>
Given the expression shown below;
1/3 + 2/5(2 - 1/2)^2
Solve the expression in bracket
1/3 + 2/5(3/2)^2
1/3 + 2/5(9/4)
Multiply the fractions
1/3 + 18/20
Find the LCM
20+36/60
56/60
28/30
14/15
Hence the resulting fractions is 14/15
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Answer:
10 : 3
Step-by-step explanation:
Convert one of the measurements so that it is in the same form as the other. (Easiest to convert m to cms so we are not working with decimals)
2.5 m = 2.5 x 100 = 250 cm (since there are 100 cm in a meter)
Therefore, as a ratio:
250 : 75
We can divide both by 5:
50 : 15
We can further divide by 5:
10 : 3
(no further simplifying)
So 2.5 m to 75cm as a ratio is 10 : 3
Answer:
4
Step-by-step explanation:
Given that:
Let the two numbers = a and b
H. C. F of the two numbers = 2
L.C.M of the two numbers = 54
If a = 27 ; b =?
The product of a and b = product of their L. C. M and H. C. F ;
HENCE ;
27 * b = 2 * 54
27b = 108
b = 108/27
b = 4
Hence, second number is 4
