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11111nata11111 [884]
3 years ago
10

Please provide your work for your answer, the answer is not much important, the work that led to the answer is what matters the

most. Provide answer too tho. Please help I dont have much time left. Will give brainliest to most thoughtful and correct answer. Thanks and have a great day everyone!

Mathematics
2 answers:
german3 years ago
4 0

Answer:

It gives you 28 different 10-digit numbers

Step-by-step explanation:

The leftmost position digit can not be 0 --- hence, it is 1, since there is no other possibilities.

The rightmost position (the "ones" position) must be 0 to provide an even number.

Hence, you have 8 remaining positions to fill with six ones and two zeros by an arbitrary way.

You can place two digits of zero among 8 positions by \frac{C 2}{8} = \frac{8=7}{2}different ways = 4*7 = 28 different ways,

Karolina [17]3 years ago
4 0

Answer:

know cares thxs for the point it don't matter anyway bc u posted this 3 weeks ago anyway so ya and also u are annoying  bc u report everyone for the most st u pid reason so i bascillily reported 2 of ur post recent

STOP IT AND GET SOME HELP

Step-by-step explanation:

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