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rewona [7]
2 years ago
13

PLEASE HELP! I NEED BOTH PARTS!

Mathematics
1 answer:
Natasha2012 [34]2 years ago
4 0

Answer:

a) Yes agree

and b) (I'm not too sure about this one but I think..) By CPCT that is Corresponding parts of congruent triangles are equal/congruent theorem.

Step-by-step explanation:

I'll use this " [ " symbol for angle.

a) yes agreed ;

AB = CB (B is the midpoint of AC)

[ ABD = [ CBD = 90°

BD = BD (common side)

--> therefore by SAS criteria triangle ABD is congruent to triangle CBD.

and by CPCT .... AD = CD .

b) AD = CD (proven by CPCT)

...answer for b you're likely suppose to write it that way. so yeah hope this helps.

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Round 2.71828 to the hearest thousandth.
Colt1911 [192]

Answer:

2.718

Step-by-step explanation:

The thousandths place is 3 to the right of the decimal (the 8).

Since the next number is 2, the number stays the same and does not round up.

Hope this helps :)

4 0
3 years ago
I need the answer for my homework
sergij07 [2.7K]

Answer:

45 for 5 and 34 for 6.

Step-by-step explanation:

You are just subtracting by 11.

7 0
2 years ago
A large spherical balloon is being deflated
artcher [175]

The formula for volume of a sphere is V = 4 /3 x π x r3 (cubed).

The original radius of the balloon is 10 ft, so when we plug that value into the equation we get 4188.79. When the balloon deflated, the new radius was 5 ft, so the new volume is 523.6. The question asks how much volume was lost, so we need to subtract 4188.79 - 523.6 and get approximately 3665.

Hope this helps! I hate taking usa test prep quizzes too haha.

7 0
2 years ago
...........answers plz
Ira Lisetskai [31]

Answer:

0

Step-by-step explanation:

m = 21, n = 12

so we just plug these into the equation

(1/3)(21) -1 -(1/2)(12)

(21/3) -1 -(12/2)

7 -1 -6

6 -6

0

3 0
2 years ago
NEED HELP!!! WILL MARK BRAINLIEST!!!
Tanzania [10]

Answer:

RTA= (x-2)·(x-11/2)/(x-2)(x-4)= (you can simplify again if you want by eliminating both (x-2)

(x-11/2)/(x-4)

Step-by-step explanation:

Ok we need to simplify the expression so:

x^2+3x-10= Bhaskara formula=

-3(±√9-4·1·(-10))/2·1=

X1=(-3+7/2)--> X1=2(R)---> (X-R)--->X-2

X2=(-3-7)/2 --> X2=11/2(R)---> (X-R)--->X-11/2

x^2-6x+8= Bhaskara formula=

6(±√36-4·1·8)/2·1=

X1=(6-2)/2=2--> X1=2(R)---> (X-R)--->X-2

X2=(6+2)/2=2--> X2=4(R)---> (X-R)--->X-4

so, The simplify expression is

(x-2)·(x-11/2)/(x-2)(x-4)=

8 0
2 years ago
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