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kirill [66]
3 years ago
7

The total amount of deductions from an employee’s gross pay is $83.20. If the gross pay is $378.18, what percent of their gross

pay is being withheld? a. 21% b. 22% c. 23% d. 24%
Mathematics
2 answers:
Inga [223]3 years ago
8 0

Answer:

Its B

Step-by-step explanation:

1 Step Forward and 2 Steps Back!

lutik1710 [3]3 years ago
5 0

The <em><u>correct answer</u></em> is:

b. 22%

Explanation:

To find the percentage withheld, we divide the amount withheld by the gross pay.  This means we divide

83.2 ÷ 378.18 = 0.2200010577 ≈ 0.22 = 22%

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Dmitrij [34]
Lets see.
55% are girls among them 79% play sport. This means 79% out of 55% girls play football.
75% * 55%
75/100 * 55%
0.75 * 55%
41.25
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Si a+b = 10; ab= 3 calcula a2 + b2
blsea [12.9K]
<h3>Solution:</h3>
  • Given, a + b = 10, ab = 3
  • Therefore,
  • (a + b)^2 = a^2 + 2ab + b^2
  • or, (10)^2 = a^2 + 2(3) + b^2
  • or, 100 = a^2 + 6 + b^2
  • or, a^2 + b^2 = 100 - 6
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<h3>Answer:</h3>

94

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3 years ago
In a group of kangaroos, the two lightest kangaroos weigh 25% of the total weight of the group. The three heaviest kangaroos wei
Maru [420]

Answer:

6 kangaroos

Step-by-step explanation:

25% + 60% = 85%

15% can be only one because the two lightest are 25% of the total.

2+1+3 = 6

4 0
4 years ago
Consider the solid S described below. The base of S is the triangular region with vertices (0, 0), (4, 0), and (0, 4). Cross-sec
alisha [4.7K]

Answer:

Volume = \frac{64}{3}

Step-by-step explanation:

Given - Consider the solid S described below. The base of S is the triangular region with vertices (0, 0), (4, 0), and (0, 4). Cross-sections perpendicular to the x-axis are squares.

To find - Find the volume V of this solid.

Solution -

Given that,

The equation of the line with both x-intercept and y-intercept as 4 is -

\frac{x}{4} + \frac{y}{4}  = 1

⇒x + y = 4

⇒y = 4 - x

Now,

Volume = \int\limits^a_b {A(x)} \, dx

where

A(x) is the area of general cross-section.

It is given that,

Cross-sections perpendicular to the x-axis are squares.

So,

A(x) = (4 - x)²

As solid lies between x = 0 and x = 4

So,

The Volume becomes

Volume = \int\limits^4_0 {(4 - x)^{2} } \, dx

             = \int\limits^4_0 {[(4)^{2}  + (x)^{2} - 8x] } \, dx

             = \int\limits^4_0 {[16  + x^{2} - 8x] } \, dx

             = {[16 x  + \frac{x^{3}}{3}  - \frac{8x^{2} }{2} ] } ^4_0

             = {[16(4 - 0)  + \frac{4^{3}}{3} - \frac{0^{3}}{3}  - 4 [4^{2} - 0^{2}]   ] }

             = {[16(4)  + \frac{64}{3} - 0  - 4 [16 - 0]   ] }

             = {[64  + \frac{64}{3}  - 64  ] }

             = \frac{64}{3}

⇒Volume = \frac{64}{3}

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