<span>From the given ((E) (U)), the
sample space for the experiment</span> is {EE, EU, UE, UU}. I am hoping that this answer has
satisfied your query and it will be able to help you in your endeavor, and if
you would like, feel free to ask another question.
Answer:
They are not equal to each other
Step-by-step explanation:
3^2 + 2^2 = C^2
9+4=C^2
13=c^2
3.6= CD
2^2 +2^2 =c^2
4+4 =c^2
8=c^2
2.8= EF
Answer:
24 eight-digit code.
Step-by-step explanation:
Frequency : 0 : 4
2 : 2
4 : 2
In total there are Eight (8) numbers and 3 frequent number ( which are 0, 2, 4 )
∴ 8 × 3 = 24.
Answer:
False
Step-by-step explanation:
There might be a chance I am wrong though sorr for the inconvinience
The minimum distance will be along a perpendicular line to the river that passes through the point (7,5)
4x+3y=12
3y=-4x+12
y=-4x/3+12/3
So a line perpendicular to the bank will be:
y=3x/4+b, and we need it to pass through (7,5) so
5=3(7)/4+b
5=21/4+b
20/4-21/4=b
-1/4=b so the perpendicular line is:
y=3x/4-1/4
So now we want to know the point where this perpendicular line meets with the river bank. When it does y=y so we can say:
(3x-1)/4=(-4x+12)/3 cross multiply
3(3x-1)=4(-4x+12)
9x-3=-16x+48
25x=51
x=51/25
x=2.04
y=(3x-1)/4
y=(3*2.04-1)/4
y=1.28
So now that we know the point on the river that is closest to Avery we can calculate his distance from that point...
d^2=(x2-x1)^2+(y2-y1)^2
d^2=(7-2.04)^2+(5-1.28)^2
d^2=38.44
d=√38.44
d=6.2 units
Since he can run at 10 uph...
t=d/v
t=6.2/10
t=0.62 hours (37 min 12 sec)
So it will take him 0.62 hours or 37 minutes and 12 seconds for him to reach the river.
