Answer:
Explanation:
Data given and notation
represent the sample mean
represent the standard deviation for the sample
sample size
represent the value that we want to test
represent the significance level for the hypothesis test.
t would represent the statistic (variable of interest)
represent the p value for the test (variable of interest)
State the null and alternative hypotheses.
We need to conduct a hypothesis in order to determine if the mean is lower than 5600, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:
(1)
t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".
Calculate the statistic
We can replace in formula (1) the info given like this:
Answer: 320 units
Explanation:
The equivalent units of production for transferred in units in the Filtering Department in August under the first-in, first-out (FIFO) method goes thus:
Total units completed= 160 units + 290 units = 450 units
Beginning WIP = 160 units
Ending WIP = 30 units
Equivalent units of production:
= 450 + 30 - 160
= 480 - 160
= 320 units
Answer:
Total cost = $3477.5
Explanation:
Given the following data;
Sales tax = 7%
Cost price = $3250.00
To find the total cost for the printer;
First of all, we would determine the sales tax
Sales tax = 7/100 * 3250
Sales tax = 7 * 32.5
Sales tax = $227.5
Now, we can find the total cost;
Total cost = sales tax + cost price
Total cost = 227.5 + 3250
Total cost = $3477.5
Answer:
for $16000 plan B is better than A
Explanation:
We are searching for the stage where Plan A's compensation is less than Plan B's compensation.
Plan A < Plan B
let total of Curt's sales be the x,
x is the basis of the commission under Plan A, but the first 5000 of sales are excluded i.e (x - 5000) from the basis of commissions under Plan B.
350 + x(0.10) < 750 + (x - 5000)(0.15)
800 -750 < (0.15) x - 5000(0.15) - (0.10)x
50 < (0.15 - 0.10)x - 750
50+750 < (0.05)x
800 < (0.05)x
16000 < x
