Y = 2x + 3

Mathematics

2 answers:

Doss [256]3 years ago

8 0

The answer would be infimnate .................

BARSIC [14]3 years ago

3 0

Answer:

Infinite solution

Step-by-step explanation:

There is 3 possible solutions to a system of linear equations:

One solution - two distinct lines that do not share y-intercept or slop intersect at a point
No solution - two distinct lines that share the same slope but not the same y-intercept never intersect and are parallel
Infinite solution - one distinct function represented two ways which in simplest form share the same slope and y-intercept

The first equation is in simplest form y=2x+3.

The second equation 2y=4x+6 when simplified becomes y=2x+3.

These are the same lines with the same slope and y-intercept. Therefore, they have infinite solutions.

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lesantik [10]

Answer:

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3 years ago

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Natali [406]

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3 years ago

Graph y = x2 + 2. Identify the vertex of the graph. Tell whether it is a minimum or maximum

Leona [35]

Vertex is -b/2a. The variable b=2 and a=2. That finds the x coordinate of the vertex. Then to find the y coordinate you just plug the number you got for x (-1/2) into the equation. Like so:
y = 2x+2
y = 2(-1/2)+2
y = -1+2
y = 1
So your vertex is ( -1/2, 1 )
To graph your vertex you take your x coordinate (-1/2) and find it on the x axis of the graph (horizontal line). Then do the same for y (1) (on the vertical axis.
Now that you have your vertex graphed you can find out if it is minimum or maximum by looking at the direction in which the slope is going. If it goes in the positive direction (up) then it is a minimum since that is the lowest point that the line touches. If it is maximum it is opposite. The line faces down and the highest point the line touches is that point.

4 0

3 years ago

Plot the vertex, focus, and directrix for the parabola represented by this equation. X=-1/12(y-2)^2+1

alukav5142 [94]

The vertex of the parabola is (1, 2), focus of the parabola is (-2, 2), and directrix x = 4.

<h3>What is a parabola?</h3>

It is defined as the graph of a quadratic function that has something bowl-shaped.

We have a parabola equation:

$\rm x = -\dfrac{1}{12}(y-2)^2+1$