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antoniya [11.8K]
2 years ago
9

Plz help urgent!! geometry test Find the measure of angle y in the figure if P is the center

Mathematics
1 answer:
Murrr4er [49]2 years ago
6 0
More info pls!!!!!!!!!
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Let u=<-5,2>, v=<-2,6>. Find 4u+3v.
charle [14.2K]

Answer:

\large\boxed{4\vec{u}+3\vec{v}=}

Step-by-step explanation:

\vec{u}=;\ \vec{v}=\\\\4\vec{u}==\\\\3\vec{v}==\\\\4\vec{u}+3\vec{v}=+==

4 0
3 years ago
A typical television newscast has three cameras. The center camera directly faces the news anchors desk. The other two cameras a
Mnenie [13.5K]
<span>150 degrees. Let's assume the center camera is pointed to at an angle of 0 degrees. Since it has a coverage of 60 degrees, then it will cover the angles from -30 to +30 degrees. Now we'll continue to use the +/- 30 degree coverage for the other two cameras. The second camera is aimed at 45 degrees, so it's range of coverage is 15 degrees to 75 degrees (45 +/- 30). Notice that the range from 15 degrees to 30 degrees is covered by 2 cameras. Now the 3rd camera is pointed at -45 degrees, so its coverage is from -15 degrees to -75 degrees. It also has an overlap with the 1st camera from -15 to -30 degrees. The total coverage of all three cameras ranges from -75 degrees to 75 degrees. That means that an arc of 150 degrees in total is covered by all three cameras.</span>
7 0
3 years ago
What is answer of the his questions show step<br><br>(8÷0.1+12×3)−2​
BARSIC [14]

Answer: I believe its 274

Step-by-step explanation: Divide 8 by 0.1 and add 12+1=13 then multiply 13 by 3 and subtract it

hope this helps

Chenn was here!

5 0
1 year ago
Read 2 more answers
What is 1/2 % of 200
Katarina [22]
One half of 200 is 100 because 200 divided by 2 is 100

P.S: Please give me brainiest answer
4 0
3 years ago
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Please help.Please show the formula,thanks.
Yuki888 [10]

Answer:

DE=6.3

Step-by-step explanation:

triangles are similar so, its sides and angles are comgruent.

side BC=side DE

side BC=6.3

side DE=6.3

<h3><u>N</u><u>o</u><u>t</u><u>e</u><u>:</u><u>i</u><u>f</u><u> </u><u>y</u><u>o</u><u>u</u><u> </u><u>n</u><u>e</u><u>e</u><u>d</u><u> </u><u>t</u><u>o</u><u> </u><u>a</u><u>s</u><u>k</u><u> </u><u>a</u><u>n</u><u>y</u><u> </u><u>question</u><u> </u><u>please</u><u> </u><u>let</u><u> </u><u>me</u><u> </u><u>know</u><u>.</u></h3>
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