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antoniya [11.8K]
2 years ago
9

Plz help urgent!! geometry test Find the measure of angle y in the figure if P is the center

Mathematics
1 answer:
Murrr4er [49]2 years ago
6 0
More info pls!!!!!!!!!
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Find the exact or approximate area of the shaded region
Lana71 [14]

Answer: 18.24 cm^2

Step-by-step explanation:

the two 135 degree angles indicate that the third angle (the one with the shaded region) is 90 degrees, which means that the shaded region is within 1/4 of the circle.

1. In order to find the area for that 1/4 region, you would have to find the area of the circle and divide it by 12

[r^2(3.14)]/4      pi is substituted by 3.14, and the radius is 8.

50.24 is the area of 1/4 of the circle.

2. Next you'd have to find the area of the triangle formed by the shaded region, and subtract the triangle from the area of the 1/4 circle.

the triangle is an isoceles triangle with two sides each valuing at 8cm, so to find the area of the triangle you would multiply the two sides (or square them since they're the same number) and divide by two

this means the triangle is 32 cm^2

3. we can subtract the 1/4 circle (50.24) by the area of the triangle (32) to get the area of the shaded region, which is <u>18.24 cm^2</u>

7 0
3 years ago
!!!!!!!!!!!!!!!!!!!!!
S_A_V [24]

Answer:

A

Step-by-step explanation:

8 0
3 years ago
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is this quadrilateral a parallelogram?If yes, state the definition or theorem that justifies your answer.​
Xelga [282]

Answer:

Yes.

Step-by-step explanation:

Yes.   Because opposite angles are congruent.

4 0
3 years ago
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Russell runs 9/10 mile in 5 minutes. At this rate, how many miles can he run in one minute?
miss Akunina [59]
9/50 is the answer I think!

I converted 9/10 to decimal to make it easier for me to solve and got 0.9

I divided 0.9 by 5 and got 0.18

I converted 0.18 to fraction and got 9/50
7 0
3 years ago
An object moves along a straight line so that at any time t , for 0≤t≤8 , its position is given by x(t)=5+4t−t2 . For what value
saul85 [17]
It’s ccccccccccccccccccccccc
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3 years ago
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