HELP IM GONNA FAIL!!!

Mathematics

2 answers:

disa [49]3 years ago

7 0

Answer:

Hope this helped don't know when this question was submitted though lol.

Nina [5.8K]3 years ago

5 0

I think that the answer is B

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The lengths of pregnancies in a small rural village are normally distributed with a mean of 262 days and a standard deviation of

RideAnS [48]

Answer:

The range in which we can expect to find the middle 68% of most pregnancies is [245 days , 279 days].

Step-by-step explanation:

We are given that the lengths of pregnancies in a small rural village are normally distributed with a mean of 262 days and a standard deviation of 17 days.

Let X = lengths of pregnancies in a small rural village

SO, X ~ Normal( $\mu=262,\sigma^{2} = 17^{2}$ )

Here, $\mu$ = population mean = 262 days

$\sigma$ = standard deviation = 17 days

Now, the 68-95-99.7 rule states that;

68% of the data values lies within one standard deviation points.

95% of the data values lies within two standard deviation points.

99.7% of the data values lies within three standard deviation points.

So, middle 68% of most pregnancies is represented through the range of within one standard deviation points, that is;

[ $\mu -\sigma$ , $\mu + \sigma$ ] = [262 - 17 , 262 + 17]

= [245 days , 279 days]

Hence, the range in which we can expect to find the middle 68% of most pregnancies is [245 days , 279 days].

5 0

3 years ago

Kim's softball team is playing in the championship game. They are losing by a score of 17 to 6. There are 4 innings to go. Kim w

meriva

(how many more needed) divided by (how many innings left)
17-6=11
4 left

11/4=2.75

needs to score 2.75 per inning (even though you can't score 0.75 point)

7 0

3 years ago

Read 2 more answers

If sin theta equals 12 divided by 13 and theta is in quadrant 2 cos20 equals? and cos theta equals?

Anni [7]

Answers:

cos(2theta) = -119/169
cos(theta) = -5/13

=====================================================

The given info is:

sin(theta) = 12/13
theta is in quadrant II

From that, we can use the pythagorean trig identity to find that cos(theta) = -5/13. Keep in mind that cosine is negative in quadrant II.

Now use the trig identity below to compute cos(2theta)

$\cos(2\theta) = \cos^2(\theta)-\sin^2(\theta)\\\\\cos(2\theta) = \left(\frac{-5}{13}\right)^2-\left(\frac{12}{13}\right)^2\\\\\cos(2\theta) = \frac{25}{169}-\frac{144}{169}\\\\\cos(2\theta) = \frac{25-144}{169}\\\\\cos(2\theta) = -\frac{119}{169}\\\\$