Answer:
The degree of fastness by which the water is rising is 210 seconds
Step-by-step explanation:
The volume of the trough when the water depth is 20 cm is first calculated
Volume of the trough (Trapezoidal Prism) = LH (A + B) × 0.5
Where L is the length of the trough, H is the height of the trough and A and B are parallel width of the top and bottom of the trough
Volume of the trough = 7 × 0.2 (0.3 + 0.7) × 0.5 = 0.7m³
The fastness at which the water is rising is = Volume ÷ water flow rate = 0.7 ÷ 0.2 = 3.5 min = 210 seconds
Increase = 14
Total =50
Percentage increase = 14/50 x 100 = 28%
I just took the test and the answer was D
50 in, 48 in, 14 in are the side lengths that form a right triangle
Mitch did not line the place values up right
