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bonufazy [111]
3 years ago
13

-x/6 + 6 = 32 Please help me! Thank you

Mathematics
2 answers:
vagabundo [1.1K]3 years ago
7 0

Answer:

-156

Step-by-step explanation:

Subtracting 6 from each side, we get

-x/6 = 26

Then multiplying by 6 from each side, we get

-x = 156

Then dividing by negative one from each side, we get

x = -156

kakasveta [241]3 years ago
5 0

Answer:

x=−156

Step-by-step explanation:

See picture...

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Please help me with this problem:Which properties justify the steps taken to solve the system?{2x−4y=183x+3y=0Drag and drop the
Hatshy [7]

First step.

If we multiply by 3 the first equation and by 2 the second equation we get the first step:

\begin{gathered} 6x-12y=54 \\ 6x+6y=0 \end{gathered}

therefore, the answer for the first box is: Multiplication property of equality.

Second step.

If we subtract both equations, we have

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then, the answer for the second box is: Subtraction property of equality

Third step.

By dividing both sides of our last result by -18, we get

y=\frac{54}{-18}=-3

then, the answer for the third step is: Division property of equality.

Fourth step.

Once we have obtained the result for variable y (which is -3), we need to find the result for variable x. So, by substituting our result for y into the first equation, we have

2x-4(-3)=18

Therefore, the answer for the fourth box is: Substitution property of equality.

Fifth step.

Then, by simplifying our last result, in which there is a product of -4 and -3, we get

2x+12=18

Thefore, the answer for the fifth box is: Simplify.

Sixth step.

Now, by subtracting 12 to both sides, we have

2x=6

then, the answer for the sixth box is: Subtraction property of equality.

Seventh step.

Finally, by dividing both sides by 2, we obtain

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Then, the answer for the seventh box is: Division property of equality.

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AURORKA [14]

Answer:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

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tresset_1 [31]

Answer:

D

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Since its less then the circle is open and the arrow goes to the left. The circle must be on -1. The answer is D.

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