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MatroZZZ [7]
2 years ago
13

Alexis bought 2 bags of apples for the fruit salad for her party. Each bag contained 13 apples. If she cuts each apple into 8 pi

eces, how many apple pieces would she have?
Mathematics
1 answer:
Lerok [7]2 years ago
4 0

Answer:

13*8=104

104*2=

<em>208</em>

Step-by-step explanation:

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At Micaela's Printing Company LLC there are two kinds of penting presses: Model A which can print 60 books per day and Model B w
devlian [24]
A+B=15 —>A+15=B(plug this into the other equation)
60a+30b=600
60a+30(a+15)=600
60a+30a+150=600
90a+150=600
90a=450
A=5 (plug back in to first equation)
A+B=15
5+B=15
B=10

They have 5 of the Model A and 10 of model B.
8 0
2 years ago
Leonard and Marcus have saved up a total of $47.00. Leonard has saved 3 dollars less than 3/5 as much as Marcus. How much has Ma
shtirl [24]

Answer:

marcus saved 31.25

Step-by-step explanation:

8 0
2 years ago
For the following system, if you isolated x in the first equation to use the Substitution Method, what expression would you subs
tatiyna
-x-2y=-4 \\ 3x+y=12 \\ \\ \hbox{the first equation:} \\ -x-2y=-4 \ \ \ \ \ \ |+2y \\ -x=2y-4 \ \ \ \ \ \ \ \ |\times (-1) \\ x=-2y+4

The expression you would substitute for x is -2y+4. The answer is d.
4 0
3 years ago
What is the solution of the following system?
erica [24]

Answer:

The answer to your question is: both lines are the same.

Step-by-step explanation:

                                   

                                             3x + 3y = 10

                                            -9x -9y = -30

Elimination method

                                            9x + 9x = 30

                                           -9x -  9y = -30

                                              0     0      0

8 0
3 years ago
Scores from an exam are normally distributed with a mean of 85 and a standard deviation of 5. Suppose 188 students take the exam
charle [14.2K]

The mean is \mu=85 and standard deviation is \sigma=5. Then the variable X\sim N(85,5).

Use substitution Z=\dfrac{X-\mu}{\sigma}=\dfrac{X-85}{5}, then the variable Z\sim N(0,1).

The probability Pr(X>80) can be calculated in the following way:

for X=80, Z=\dfrac{80-85}{5} =-1 and Pr(X>80)=Pr(Z>-1). From the diagram Pr(Z>-1)=0.34+0.34+0.135+0.025=0.84.

Conclusion: if 188 students take the exam, then 188·0.84=157.92 (157) would receive a score above 80

4 0
3 years ago
Read 2 more answers
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