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ale4655 [162]
3 years ago
14

There are six songs on your playlist. With

Mathematics
1 answer:
Viefleur [7K]3 years ago
3 0

Answer:

1 in 36

Step-by-step explanation:

6 * 6

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Trapezoid QRST has two right angles. A 5-in.altitude can be drawn dividing QRDT into a rectangle and an isosceles right triangle
Vika [28.1K]

Answer:

The area of the trapezoid is 57.5 square inches

Step-by-step explanation:

we know that

The trapezoid QRST can be divided into a rectangle QRDT and an isosceles right triangle RSD

see the attached figure to better understand the problem

step 1

The area of rectangle is given by the formula

A=((QR)(RD)

we have

RD=5\ in ----> altitude

QR=9\ in

substitute

A=((9)(5)=45\ in^2

step 2

Find the area of the isosceles right triangle

The area of triangle is given by the formula

A=\frac{1}{2}(RD)(DS)

we have

RD=DS=5\ in ---> because is an isosceles triangle

substitute

A=\frac{1}{2}(5)(5)=12.5\ in^2

step 3

Adds the areas

A=45+12.5=57.5\ in^2

3 0
3 years ago
Read 2 more answers
Is (a + b) and (a - b)? perfect square trinomials?<br> O True<br> O False
lisabon 2012 [21]

Answer:

False

Step-by-step explanation:

Pos and negs cannot be perfect square trinomials

8 0
2 years ago
Read 2 more answers
HELP ITS DUE IN A FEW MINS WITH MY OTHER QUESTION BUT I NEED MY LAST HELP PLS AND TYYY I WOULD APPRECIATE IT SM &lt;3
kolbaska11 [484]

Answer:

y=3/4x+1

Step-by-step explanation:

up 3 right 4. U better hurry up and answer that question my guy!

6 0
2 years ago
John is driving on a highway.He uses one gallon of gas every 25 miles he drives.The distanc, D (in miles), he travels on g gallo
Cloud [144]

Answer:

I need help on this thing too someone help

Step-by-step explanation:

6 0
3 years ago
A certain car depreciates such that its value at the end of each year is p % less than its value at the end of the previous year
icang [17]

Answer:

b(b/a)^2

Step-by-step explanation:

Given that the value of the car depreciates such that its value at the end of each year is p % less than its value at the end of the previous year and that car was worth a dollars on December 31, 2010 and was worth b dollars on December 31, 2011, then

b = a - (p% × a) = a(1-p%)

b/a = 1 - p%

p% = 1 - b/a = (a-b)/a

Let the worth of the car on December 31, 2012 be c

then

c = b - (b × p%) = b(1-p%)

Let the worth of the car on December 31, 2013 be d

then

d = c - (c × p%)

d = c(1-p%)

d = b(1-p%)(1-p%)

d = b(1-p%)^2

d = b(1- (a-b)/a)^2

d = b((a-a+b)/a)^2

d = b(b/a)^2 = b^3/a^2

The car's worth on December 31, 2013 =  b(b/a)^2 = b^3/a^2

4 0
3 years ago
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