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Hoochie [10]
2 years ago
12

What are the steps for using a compass and straightedge to construct a square?

Mathematics
2 answers:
aniked [119]2 years ago
7 0

Answer:

Ooof

Step-by-step explanation:

Nonamiya [84]2 years ago
5 0

Answer:

yikes ok

Step-by-step explanation:

STEPS:

Using your straightedge, draw a reference line, if one is not provided.

Copy the side of the square onto the reference line, starting at a point labeled A'.

Construct a perpendicular at point B' to the line through .

Place your compass point at B', and copy the side of the square onto the perpendicular.

id.k if this helps at all prob not but trying bc id.k

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melomori [17]
N'(-2,2)
G'(-2,-4)
H'(6,-4)
5 0
3 years ago
Item 20 An online T-shirt store is having a sale. The original price of each T-shirt is p dollars. The store sells 20 T-shirts a
Bumek [7]

discount per tshirt=(originalprice-discountedprice)/numberofshirtssold

20 tshirts

originaprice=20*p=20p

discountedprice=20p-60

numberofshirtssold=20


discountpershirt=(20p-(20p-60))/20

discountpershirt=(20p-20p+60)/20

discountpershirt=(60)/20

discountpershirt=3

the discount per tshirt is $3.00 per shirt

6 0
3 years ago
Read 2 more answers
What is the length of segment AE?
nexus9112 [7]

Answer:

AE=\frac{50}{3}\ units

Step-by-step explanation:

step 1

In the right triangle ABC

Applying the Pythagoras Theorem fin the hypotenuse AC

AC^{2} =AB^{2}+BC^{2}

substitute

AC^{2} =6^{2}+8^{2}

AC^{2} =100

AC =10\ units

step 2

we know that

If two figures are similar, then the ratio of its corresponding sides is equal

so

\frac{AB}{CD}=\frac{AC}{CE}

substitute and solve for CE

\frac{6}{4}=\frac{10}{CE}\\ \\CE=4*10/6\\ \\CE=\frac{20}{3}\ units

step 3

Find the length of segment AE

AE=AC+CE

substitute the values

AE=10\ units+\frac{20}{3}\ units=\frac{50}{3}\ units

6 0
3 years ago
Can someone pls help??
Vlad1618 [11]

Answer:

a. The y coordinates for A are either 10 or -14

b.  The y coordinates for A are either -11 or 7

Step-by-step explanation:

distance = sqrt ((x2-x1)^2+(y2-y1)^2)

We know Point B and the x coordinate of point A as well as the distance

15 = sqrt ((-4-5)^2+(-2-y1)^2)

15 = sqrt ((-9)^2+(-2-y1)^2)

15 = sqrt (81+(-2-y1)^2)

Square each side

15^2 =sqrt (81+(-2-y1)^2)^2

225 =  81+(-2-y1)^2

Subtract 81 from each side

225-81 = 81-81 +(-2-y1)^2

144 = (-2-y1)^2

Take the square root of each side

±sqrt 144 = sqrt(-2-y1)^2

±12 = (-2-y1)

Add 2 to each side

2±12 = 2-2-y1

2±12 = -y1

14 = -y1  or -10 = -y1

Multiply by -1

-14 = y1  or 10 = y1

The y coordinates for A are either 10 or -14

Now move B to -7,-2

15 = sqrt ((-7-5)^2+(-2-y1)^2)

15 = sqrt ((-12)^2+(-2-y1)^2)

15 = sqrt (144+(-2-y1)^2)

Square each side

15^2 =sqrt (144+(-2-y1)^2)^2

225 =  144+(-2-y1)^2

Subtract 144 from each side

225-144 = 144-144 +(-2-y1)^2

81 = (-2-y1)^2

Take the square root of each side

±sqrt 81 = sqrt(-2-y1)^2

±9 = (-2-y1)

Add 2 to each side

2±9 = 2-2-y1

2±9 = -y1

11 = -y1  or -7 = -y1

Multiply by -1

-11 = y1  or 7 = y1

The y coordinates for A are either -11 or 7

3 0
3 years ago
If an independent-measures design is being used to compare two treatment conditions, then how many different groups of participa
Serhud [2]

Answer:

2 groups and 1 score for each participant

Step-by-step explanation:

An independent measures design is a defined as a research method whereby multiple experimental groups are examined and the participants will only be in one group. Now, each participant will only be affected by one condition of the independent variable during the experiment.

In the question given, we want to use the method I just described to compare two treatment conditions.

This means that there will be two groups and each participant in both groups will be assigned one score.

7 0
2 years ago
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