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3 years ago

HELPPP PLEASE WILL MARK BRAINLEST IF RIGHT!!!

Mathematics

2 answers:

Sholpan [36]3 years ago

5 0

Answer:

C i think

Step-by-step explanation:

Feliz [49]3 years ago

5 0

Answer:

C) 18 inches

Step-by-step explanation:

lets call the shortest side x.

that means the second side is 3x

the third side is x + 5

the perimeter of the triangle is 95 inches.

using this information, you can make the following equation:

x + 3x + x + 5 = 95

subtract 5 from both sides.

x + 3x + x = 90

5x = 90

x = 18

the shortest side is 18 inches long

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Based in the graph, what is the initial value of the linear relationship

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You spend a $20 per turn on a fair game to win $50 for each win. you lose the first round but win the next two rounds.

Brums [2.3K]

Answer:

Step-by-step explanation:

ok, so since you want to find out what the profit is, first you take the times you won and multiply the amount you got for winning so 50*2=100. now that you have 100 you take the money you spent and multiply it by the number of times you played the game so 20*3=30. now that you have those you have everything you need to finish the question. you take the amount you spent per play (30) and subtract it from what you won (100). 100-30=70

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Determine if the sequence is arithmetic or geometric. Then identify the next term in the sequence 0.2, 1, 5, 25,…

Tatiana [17]

Answer:

C. geometric; 125

Step-by-step explanation:

first term(a) = 0.2

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Tn = ar^ n -1

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hope it helps :)

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3 years ago

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23. A certain type of gasoline is supposed to have a mean octane rating of at least 90. Suppose measurements are taken on of 5 r

Nostrana [21]

Answer:

a) $p_v =P(Z$

b) Since $p_v$ we can reject the null hypothesis at the significance level given. So based on this we can commit type of Error I.

Because Type I error " is the rejection of a true null hypothesis".

c) $P(\bar X >90)=1-P(Z$

$1-P(Z$

d) For this case we need a z score that accumulates 0.02 of the area on the right tail and 0.98 on the left tail and this value is z=2.054

And we can use this formula:

$2.054=\frac{90-89}{\frac{0.8}{\sqrt{n}}}$

And if we solve for n we got:

$n = (\frac{2.054 *0.8}{1})^2=2.7 \approx 3$

Step-by-step explanation:

Previous concepts and data given

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

We can calculate the sample mean and deviation with the following formulas:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

$\bar X=88.96$ represent the sample mean

$s=1.011$ represent the sample standard deviation

n=5 represent the sample selected

$\alpha$ significance level

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is less than 90, the system of hypothesis would be:

Null hypothesis: $\mu \geq 90$

Alternative hypothesis: $\mu < 90$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{88.96-90}{\frac{0.8}{\sqrt{5}}}=-2.907$

Part a

P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=5-1 = 4$

Then since is a left tailed test the p value would be:

$p_v =P(Z$

Part b

Since $p_v$ we can reject the null hypothesis at the significance level given. So based on this we can commit type of Error I.

Because Type I error " is the rejection of a true null hypothesis".

Part c

We want this probability:

$P(\bar X$

The best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

If we apply this formula to our probability we got this:

$P(\bar X >90)=1-P(Z$

$1-P(Z$

Part d

For this case we need a z score that accumulates 0.02 of the area on the right tail and 0.98 on the left tail and this value is z=2.054

And we can use this formula:

$2.054=\frac{90-89}{\frac{0.8}{\sqrt{n}}}$

And if we solve for n we got:

$n = (\frac{2.054 *0.8}{1})^2=2.7 \approx 3$

7 0

3 years ago