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Vika [28.1K]
2 years ago
15

What does k^2 -8k-20=0

Mathematics
2 answers:
Karolina [17]2 years ago
7 0
k^{2}-8k-20=0 \\ (k-10)(k+2)=0 \\  \\ k-10=0 \\ k=10 \\  \\ k+2=0 \\ k=-2 \\  \\ \boxed{k=-2\ and\ 10}
victus00 [196]2 years ago
3 0
K² - 8k - 20 = 0
k = <u>-(-8) +/- √((-8)² - 4(1)(-20))</u>
                       2(1)
k = <u>8 +/- √(64 + 80)</u>
                 2
k = <u>8 +/- √(144)
</u>              2<u>
</u>k = <u>8 +/- 12</u><u>
</u>            2
k = <u>8 + 12</u>          k = <u>8 - 12</u>
          2                        2
h = <u>20</u>                k = <u>-4</u>
       2                        2
x = 10                k = -2
<u />
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This problem has been solved! See the answer Determine Um (mode ), average U, and Urms for a group of ten automobiles clocked by radar at speeds 38,44,48,50,55,55,57,58 and 60mi/h respectively
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HELLLPPP me plzz<br> Just help me find the area of this.
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Answer:10

Step-by-step explanation:

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Assume that you assign the following subjective probabilities for your final grade in your econometrics course (the standard GPA
rodikova [14]

Answer:

E(X) = 4*0.2 +3*0.5+ 2*0.2 +1*0.8+ 0*0.02= 2.78

So then the best answer for this case would be:

C. 2.78

Step-by-step explanation:

For this case we have the following probabability distribution function given:

Score         P(X)

A= 4.0       0.2

B= 3.0       0.5

C= 2.0       0.2

D= 1.0        0.08

F= 0.0       0.02

______________

Total          1.00

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

If we use the definition of expected value given by:

E(X) = \sum_{i=1}^n X_i P(X_I)

And if we replace the values that we have we got:

E(X) = 4*0.2 +3*0.5+ 2*0.2 +1*0.8+ 0*0.02= 2.78

So then the best answer for this case would be:

C. 2.78

3 0
3 years ago
2√63 what is the radical
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Step-by-step explanation:

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2x(squared) + 23x-19=0
Helen [10]
Use quadratic formula

for ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^2-4ac} }{2a}

given
2x^2+23x-19=0
a=2
b=23
c=-19

x=\frac{-23+/- \sqrt{23^2-4(2)(-19)} }{2(2)}
x=\frac{-23+/- \sqrt{529-152} }{4}
x=\frac{-23+/- \sqrt{377} }{4}

x=\frac{-23+ \sqrt{377} }{4} or \frac{-23- \sqrt{377} }{4}
7 0
3 years ago
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