Answer:
A.)
arr[0] = 10;
arr[1] = 10;
Explanation:
Given the array:
arr = {1,2,3,4,5}
To set the first two elements of array arr to 10.
Kindly note that ; index numbering if array elements starts from 0
First element of the array has an index of 0
2nd element of the array has an index of 1 and so on.
Array elements can be called one at a time using the array name followed by the index number of the array enclosed in square brackets.
arr[0] = 10 (this assigns a value of 10 to the index value, which replace 1
arr[1] = 10 (assigns a value of 10 to the 2nd value in arr, which replaces 2
Answer:
The answer to this question can be described as follows:
Explanation:
Relational data model:
The use of data tables to organize sets of entities into relationships requires a relational data model. this model work on the assumption, which is a primary key or code, that is included in each table configuration. The symbol for "relational" data links and information is used by other tables.
Model Design:
This model is used for database management, it consists of structure and language consistency. It is design in 1969.
Importance of data model:
This provides a common standard for processing the potentially sound data in machines, that was usable on almost any one device.
Big Data:
It moves to locate new and innovative ways to handle large volumes of authentication tokens and to gather business insights when offering high efficiency and usability at an affordable cost at the same time.
For applying the filter you need to select the data on which you want to apply it so it will allow you to look at only data you select from the filter options.
Could be anything?
Maybe you get an email from them on their PC, which means they have internet
Answer:
The Anonymous Block will be:
1 DECLARE
2
3 lv_grade_row grade%rowtype;
4 lv_gr_avg grade.gr_t1%type;
5 lv_std_name varchar2(80);
6 cursor cursor_grade is select * from grade;
7
8 BEGIN
9
10 select avg(gr_t1) INTO lv_gr_avg from grade;
11 open cursor_grade;
12 fetch cursor_grade INTO lv_grade_row;
13
14 while cursor_grade%found loop
15
16 if
17 lv_grade_row.gr_t1>lv_gr_avg then lv_std_name :=
lv_grade_row.std_fname|| ' ' ||lv_grade_row.std_lname|| ' ' ||
lv_grade_row.gr_t1;
18 dbms_output.put_line(lv_std_name);
19
20 end if;
21 fetch cursor_grade into lv_grade_row;
22
Explanation:
