It is called Windows Explorer referred as explorer.exe<span />
Answer:
Social Engineering Attack
Explanation:
The exploitation of individuals in order to gain confedential information is a Social Engineering Attack. These attacks typically take advanage of one's emotions or they use inpersonaltion to steal data.
read more here: https://www.webroot.com/us/en/resources/tips-articles/what-is-social-engineering
Lmk if this helps! :)
The Network Mapper (Nmap) commands that would be useful on this test network are:
- nmap xxx.xxx.x.x -p
- nmap xxx.xxx.x.x -A
<h3>What is a
penetration test?</h3>
A penetration test can be defined as a cybersecurity technique that simulates a cyber attack against an end user's computer system, so as to scan, identify, test and check for exploitable vulnerabilities in the following:
This ultimately implies that, a penetration test avails an tester the ability to exploit a weakness and potential security threats on a test network as a privileged user, during vulnerability assessments of the system.
<h3>The Network Mapper (Nmap) commands.</h3>
In this scenario, the Network Mapper (Nmap) commands that would be useful on this test network are:
- nmap xxx.xxx.x.x -p
- nmap xxx.xxx.x.x -A
Read more on penetration test here: brainly.com/question/25813524
Answer: money
Explanation: money is life and the air is fat is full of fart
JAVA programming was employed...
What we have so far:
* Two 2x3 (2 rows and 3 columns) arrays. x1[i][j] (first 2x3 array) and x2[i][j] (second 2x3 array) .
* Let i = row and j = coulumn.
* A boolean vaiable, x1rules
Solution:
for(int i=0; i<2; i++)
{
for(int j=0; j<3; j++)
{
x1[i][j] = num.nextInt();
}
}// End of Array 1, x1.
for(int i=0; i<2; i++)
{
for(int j=0; j<3; j++)
{
x2[i][j] = num.nextInt();
}
}//End of Array 2, x2
This should check if all the elements in x1 is greater than x2:
x1rules = false;
if(x1[0][0]>x2[0][0] && x1[0][1]>x2[0][1] && x1[0][2]>x2[0][2] && x1[1][0]>x2[1][0] && x1[1][1]>x2[1][1] && x1[1][2]>x2[1][2])
{
x1rules = true;
system.out.print(x1rules);
}
else
{
system.out.print(x1rules);
}//Conditional Statement
