Answer:
A=8x-8
B=5x+25
A=B(BEING corresponding angles)
8x-8=5x+25
8x-5x=25+8
3x=33
x=33/3
x=11
now 8x-8= 8×11-8
= 88-8
=80
5x+25= 5×11+25
=55+25
= 80
A=B#
The computation shows that the placw on the hill where the cannonball land is 3.75m.
<h3>How to illustrate the information?</h3>
To find where on the hill the cannonball lands
So 0.15x = 2 + 0.12x - 0.002x²
Taking the LHS expression to the right and rearranging we have:
-0.002x² + 0.12x -.0.15x + 2 = 0.
So we have -0.002x²- 0.03x + 2 = 0
I'll multiply through by -1 so we have
0.002x² + 0.03x -2 = 0.
This is a quadratic equation with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25.
The second solution y = 0.15 * 25 = 3.75
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Complete question:
The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?
Answer:
2 7/24
Step-by-step explanation:
1 5/8 + 2/3
1 15/24 + 16/24
1 31/24 = 2 7/24
If my answer is incorrect, pls correct me!
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-Chetan K
-9=6/v
You have to multiply v both sides because
6/v x v = 6 and helps you get rid of the v on the right side.
If you multiply by 6, 6/v x 6 = 36/v, that’s why it don’t work.
Answer:
-9=6/v
-9v=6
v=-6/9
v=-2/3
Answer:
8 9/10
Step-by-step explanation:
89 goes into 10 8 times.
8x10=80.
89-80=9
So the answer is 8 9/10
