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gizmo_the_mogwai [7]
3 years ago
9

they want to collect 1000 cans of food. they need to collect 8 times as many cans as they already have in order to reach their g

oal. how many cans do they already have? Explain the answer
Mathematics
2 answers:
MAVERICK [17]3 years ago
5 0
Answer: 125 cans

Pay attention to the word "times". "Times" means to multiply. We don't know how many cans we have right now. If we want to get up to 1000 cans of food. And we need to get 8 'times' the amount we already have, why not do the opposite of multilpication, and divide. So, you divide 1000 by 8. You get 125. Now, you can multilpy 125 by 8 and get 1000.

Hope this helps.
lyudmila [28]3 years ago
3 0
Divide 1000 by 8 which would give you 125. So they have 125 cans and they need to collect 8 times as many, meaning 8 times of what they have which is 125. And 125 times 8 is equal to 1000. YOU'RE WELCOME :D
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Answer (Note: the bold are answers):

First question answer:

Point = (3,1)

Slope = 3

y = 3x + b

(1) = 3(3) + b

1 = 9 + b

1 - 9 = b

-8 = b

y = 3x - 8

The second question answer:

y = mx + b

Get two points:

(3,-7) and (4,-11)

m = -11 - (-7) / 4 - 3

m = -11 + 7 / 1

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Answer:

A ; 23rd century

Step-by-step explanation:

Here, we want to select which of the options is next to have a descending year.

Since all are in the same century i.e 20-something, we do not have an issue with the first digit.

What we need to work on is the last three digits;

We can have 2210, we can have 2321, we can have 2432, we can also have 2543 and so on.

The most recent of all these is the year 2210, so what century does this belong?

Kindly note that, the years 2001-2100 belong to the 21st century.

The years 2101-2200 belong to the 22nd century while the years 2201-2300 belong to the 23rd century

The year we are looking to place is the year 2201 and thus belongs to between 2201-2300 which is the 23rd century

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The domain of the inverse of a relation is the same as the range of the original relation. In other words, the y-values of the relation are the x-values of the inverse.

Thus, domain of f(x): x∈R = range of f¯¹(x)

and range of f(x): x∈R =domain of f¯¹(x)

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