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Illusion [34]
3 years ago
7

point P (-4,0) lies on the directed line segment AE. The endpoints are A (2,-6) and E(x,y). What are the cooridinates of point E

such that AP is 3/4 of the distance from A to E?
Mathematics
1 answer:
irakobra [83]3 years ago
5 0

Answer:

Umm….. I really don’t know….

Step-by-step explanation:

Sorry……

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If x equals 5 and y equals negative 2 evaluate following expressions 7(2x-3y)
Thepotemich [5.8K]

Answer:

given

x=5

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expression :-> 7(2(5)-3(-2))

7(10+6)

7 * 16

112

therefore 112 is ur ans

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Can someone help me please
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Step-by-step explanation:

plz mark me as brainliest

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Please help me with 2b ASAP. <br> Really appreciate it!!
Bogdan [553]

f(x)=\dfrac{x^2}{x^2+k^2}

By definition of the derivative,

f'(x)=\displaystyle\lim_{h\to0}\frac{\frac{(x+h)^2}{(x+h)^2+k^2}-\frac{x^2}{x^2+k^2}}h

f'(x)=\displaystyle\lim_{h\to0}\frac{(x+h)^2(x^2+k^2)-x^2((x+h)^2+k^2)}{h(x^2+k^2)((x+h)^2+k^2)}

f'(x)=\dfrac{k^2}{x^2+k^2}\displaystyle\lim_{h\to0}\frac{(x+h)^2-x^2}{h((x+h)^2+k^2)}

f'(x)=\dfrac{k^2}{x^2+k^2}\displaystyle\lim_{h\to0}\frac{2xh+h^2}{h((x+h)^2+k^2)}

f'(x)=\dfrac{k^2}{x^2+k^2}\displaystyle\lim_{h\to0}\frac{2x+h}{(x+h)^2+k^2}

f'(x)=\dfrac{2xk^2}{(x^2+k^2)^2}

\dfrac{k^2}{(x^2+k^2)^2} is positive for all values of x and k. As pointed out, x\ge0, so f'(x)\ge0 for all x\ge0. This means the proportion of occupied binding sites is an increasing function of the concentration of oxygen, meaning the presence of more oxygen is consistent with greater availability of binding sites. (The question says as much in the second sentence.)

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Solve the equation. |3 − w| = −2
gizmo_the_mogwai [7]
Absolute value represents distance. Distances can't be negative. 

So it's impossible to have |3-w| be some negative value. 

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A number cube is rolled 25 times. A number less than four comes up 20 times. What is the experimental probability that a number
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It would be 20 because the highest number is 25
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