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Slav-nsk [51]
3 years ago
6

What are all possible values for x in the equation x^3=375?

Mathematics
1 answer:
melisa1 [442]3 years ago
8 0

Answer:

x=5\sqrt[3]{3} or 7.21

Step-by-step explanation:

x³ = 375

You have to take the square root and have the index 3:

You have to have the index 3 because x is cubed and you have to get rid of the cubed sign since a normal square root is for when the exponent is 2:

\sqrt[3]{x^3} =\sqrt[3]{375} \\x=5\sqrt[3]{3}

In decimal form (rounded to hundredths):

7.21

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LenaWriter [7]

Answer:

Juan- 1c+6d+5g

Together- 3c+9d+6g+3h

Step-by-step explanation:

Add their pets together

7 0
2 years ago
Read 2 more answers
Idk this pls help don’t understand.
lawyer [7]

Answer: 60, but I got other answers to but 60 was my first.

sorry if wrong.

Step-by-step explanation:

7 0
3 years ago
Simplify:0.3(x-2y)+0.5x-y
astraxan [27]

Answer:

0.3[x-2y] + 0.5x - y


Use the distributive property: a(b-c) = ab - ac


0.3x - 0.6y + 0.5x - y


Now, add/subtract all like terms


0.3x + 0.5x - 0.6y - y


0.8x - 1.6y


If you want, we can simplify that down further to:


0.8(x - 2y)



7 0
3 years ago
Read 2 more answers
??????????????????????
natita [175]

Answer:

Figure out what x is for both equations, then you can tell if the equations are the same

Step-by-step explanation:

1. 4x+1=9

x = 2

4 x 2= 8

2x+1=5

x = 2

2 x 2 = 4

4 does not = 9 so no.

4 0
3 years ago
How many 7-digit numbers can be
padilas [110]

Answer: 5040 7-digit numbers

Step-by-step explanation:

Permutations:

1: 1 ==> 1 permutation ==> 1 ==> 1!

12: 12, 21 ==> 2 permutations ==> 1*2 ==> 2!

123: 123, 132, 213, 231, 312, 321 ==> 6 permutations ==> 1*2*3 ==> 3!

7-digits: 7!=

1*2*3*4*5*6*7=5040 7-digit numbers

4 0
2 years ago
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