Question

Help please!!! ON THISSS (i will report you if not answered seriously) :))

Answer 1

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$XCV \: \: angle = \frac{XWV \: \: arc}{2}$

Multiply sides by 2

$2 \: XCV \: \: angle = XWV \: \: arc$

$XWV \: \: arc = 2 × XCV \: \: angle$

$XWV \: \: arc = 156°$

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$XWV \: \: arc + VCX \: \: arc = 360°$

$156° + VCX \: \: arc = 360°$

Subtract sides 156°

$-156° + 156° + VCX \: \: arc = -156° + 360°$

$VCX \: \: arc = 204°$

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$XWV \: \: angle = \frac{XCV \: \: arc}{2}$

$17x = \frac{204}{2}$

$17x = 102$

Divide sides by 17

$\frac{17x}{17} = \frac{102}{17}$

$x = 6$

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Sum of the interior angles of XWVC equal 360° .

Thus in XWVC :

$X + W + V + C = 360°$

$(9y) + (17x) + (6y) + (78°) = 360°$

$15y + 17x + 78° = 360°$

$15y + 17(6) + 78° = 360°$

$15y + 102° + 78° = 360°$

$15y + 180° = 360°$

Subtract sides 180°

$15y + 180° - 180° = 360° - 180°$

$15y = 180°$

Divide sides by 15

$\frac{15y}{15} = \frac{180}{15}$

$y = 12$

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$X = 9y$

$X = 9(12)$

$X = 108°$

$V = 6y$

$V = 6(12)$

$V = 72°$

$W = 17x$

$W = 17(6)$

$W = 102°$

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