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poizon [28]
3 years ago
5

Here take my final 16 pts I need help with this Bella has one quiz left to take. On the first 5 quizzes, she received a 74%, 92%

, 83%, 98%, and 100%. What must Bella score on her quiz to get an 88% in the class. Data set Below74%,92%,83%,98%,100%? NO LINKS! or in this case 8pts
Mathematics
2 answers:
BigorU [14]3 years ago
7 0
Answer is 95 explanation calculator
lukranit [14]3 years ago
6 0

Answer:

95

Step-by-step explanation:

Required Average

=

80

Let the required grade be

x

.

Average

=

Sum of

n

numbers

n

So

80

=

76

+

84

+

65

+

x

4

320

=

225

+

x

x

=

320

−

225

x

=

95

Therefore, the required grade is

95

.

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Tina and Zion earn $38 per week for delivering newspapers. Tina worked for x weeks and earned an additional total bonus of $15.
sergejj [24]

Answer:

it would be (38x+15)+38y

Step-by-step explanation:

x=number of weeks

38 times x=38x

53x=53 weeks

bonus of 15=38x+15

3 0
3 years ago
What are the coefficients in the expression 5x3 + 14x2 - 2x + 6?
Lostsunrise [7]

Answer: 5,14 and -2

Step-by-step explanation:

The coefficient  is the number next to the variable.

So this case the coefficients are 5,14 and -2

6 0
3 years ago
Read 2 more answers
Jason and Megan are brother and sister. Jason is 4 years older than Megan.If Jason is 16 yearsold write and solve an equation to
Eva8 [605]
16-4=12 is the answer.
8 0
3 years ago
Hannah made a ramp for her grandfather who was in a wheelchair. The ramp was 10 ft long and it was 5 ft away from the porch step
lianna [129]

Given :

Length of ramp( Hypotenuse ), l = 10 ft .

Length of base, b = 5 ft .

To Find :

How high were the porch steps.

Solution :

Let, height is h.

By Pythagoras theorem :

b^2+h^2=l^2\\\\h=\sqrt{l^2-b^2}\\\\h=\sqrt{10^2-5^2}\\\\h = \sqrt{75}\\\\h = 5\sqrt{3}\ ft

Hence, this is the required solution.

3 0
3 years ago
2019 Chapter Sprint Round, #20
nadezda [96]

Answer:

Speed\ of\ car=38\ km/h

Step-by-step explanation:

Distance Covered by Horse:

Speed\ of\ horse=50\ km\h=50\times \frac{1000}{60}\ meter/ minute\\\\Speed\ of\ horse=\frac{2500}{3}\ meter/minute\\\\Distance\ covered\ in\ 4\ minutes=speed\times time=\frac{2500}{3}\times 4\\\\Distance\ covered\ in\ 4\ minutes=\frac{10000}{3}\ meters\\\\

Distance covered by Car:

Let\ speed\ of\ car=x\ meter/minute\\\\time=4\ minutes\\\\Distance\ covered=speed\times time=4\times x=4x

Distance\ covered\ by\ horse=Distance\ covered\ by\ car+800\\\\\frac{10000}{3}=4x+800\\\\4x=\frac{10000}{3}-800\\\\4x=\frac{7600}{3}\\\\x=\frac{7600}{3\times 4}\ meter/minute\\\\x=\frac{7600}{3\times 4}\times \frac{60}{1000}\ km/h\\\\x=38\ km/h

7 0
3 years ago
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