The number of ways it is possible for the gold, silver, and bronze medals to be awarded is 1320 ways
<h3>Permutation and Combination</h3>
Permutation are related to arrangement and combination has to do with selection.
If there are 12 teams, each representing a different country and the possible awards are gold, silver, and bronze medals, the number of ways they can be selected is given as:
12P3 = 12!/(12-3)!
12P3 = 12!/9!
12P3 = 12 * 11 * 10
12P3 = 1320 ways
Hence the number of ways it is possible for the gold, silver, and bronze medals to be awarded is 1320 ways
Learn more on permutation here: brainly.com/question/1216161
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Percent increase is:
Change/original * 100
(29975-24400)/24400
5575/24400= .228 * 100=
22.8%
Answer:
I love algebra anyways
The ans is in the picture with the steps how i got it
(hope this helps can i plz have brainlist :D hehe)
Step-by-step explanation:
Answer:
First we will split trapezium on two geometric figure.
One is rectangle and the second is right triangle.
When we subtract 11-4=7cm we get one cathetus of the right triangle a=7cm also we know hypotenuse which is c=16cm.
We will use Pythagorean theorem to find the second cathetus b
b=√16∧2-7∧2= √256-49= √207 ≈ 14.39cm =DC =>
AC =√(DC)∧2+(AD)∧2= √14.39∧2+11∧2= √207+121= √328= 18.1cm
AC=18.1cm
Good luck!!
Let B be the event that Andrea passes her test, and let A be the event
<span>that she studies. We are given that P(A and B) = 17/20, and that P(A) = 15/16. </span>
<span>Now the probability that Andrea passes her test given that she has studied </span>
<span>is represented by P(BlA). The formula your teacher gave you can be written as </span>
<span>P(BlA) = P(A and B) / P(A). </span>
<span>So P(BlA) = P(A and B) / P(A) = (17/20) / (15/16) = (17/20)*(16/15) = 68/75.</span>
