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Ulleksa [173]
3 years ago
14

Bab needs help with Algebra two homework. show work please! Also I'll give brainliest!

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
3 0

Answer:

1.  The y values are decreasing by 16  7 and 4 then rising by 7 and 16 so the line of symmetry is at -4 or 4

2. f = g(x) function just like g = f(x) function so say f value table or g(x) function

3.  y = g(x) = -4  when x = 0

4.  y - 0 = - 4x   means the same as y = -4x

5.  [0 , -4] is the vertex

6.  6(5) = 30

next page

7 the y values are increasing by 3/4 , 11/5, 1,  7/1 and  8.5 / 1

which means thy are increasing minimum by 1/1.5 and could be a square function.

8. This is a g function or  a f(x).

9. y intercept is 1

10  common ratio is  0:1

11 equation for the table is  y = x -1

12.  5.400

next page

13.

The values for y are decreasing by 2 then drop by 12 from -2/14 to 0/-2 then increase again at a rate of 20 and decrease slightly to 18 being  -2/-20

we can see this as -2/16 ,-2/14 , 0/-2  2/ -22 meaning the line of symmetry is not clear as we cannot see an average without working out the mean or adding all the totals up.

14.  p(x) function or q value.

15.  the y intercept is -2

16. the equation for this table is y = x-2

17.

The value for p(4) is same method divide smaller into larger then times x 4

-20/-2 = 10  

then -11 x 10 = -110

18. slope = -2

17) if they were asking for value for 4(p) is  16/ -2 = 8 and  -2 / 4  = 0.5/ 8 this shows 8 so 4 is half this value = 0.24 / 4  meaning x = 0.24

Step-by-step explanation:

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Say a hacker has a list of n distinct password candidates, only one of which will successfully log her into a secure system. a.
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The probability is \frac{1}{n}

Step-by-step explanation:

If she has n distinct password candidates and only one of which will successfully log her into a secure system, the probability that her first first successful login will be on her k-th try is:

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P=\frac{n-1}{n} *\frac{n-2}{n-1} *\frac{1}{n-2} = \frac{1}{n}

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A random sample of 10 shipments of stick-on labels showed the following order sizes.10,520 56,910 52,454 17,902 25,914 56,607 21
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Answer:

Confidence Interval: (21596,46428)

Step-by-step explanation:

We are given the following data set:

10520, 56910, 52454, 17902, 25914, 56607, 21861, 25039, 25983, 46929

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{340119}{10} = 34011.9

Sum of squares of differences = 551869365.6 + 524322983.6 + 340111052.4 + 259528878 + 65575984.41 + 510538544 + 147644370.8 + 80512934.41 + 64463235.21 + 166851472.4 = 2711418821

S.D = \sqrt{\frac{2711418821}{9}} = 17357.09

Confidence interval:

\mu \pm t_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

t_{critical}\text{ at degree of freedom 9 and}~\alpha_{0.05} = \pm 2.2621

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