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MaRussiya [10]
3 years ago
15

The graph shows how the value of a car changes over

Mathematics
1 answer:
bearhunter [10]3 years ago
6 0

Answer: c

Step-by-step explanation: guesss

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Find the sum of even numbers from 34 to 234 inclusive
valentinak56 [21]
We have 

AP = 34,36,38......,234

a, (first term) = 34

n ( total terms ) =?

d ( common difference ) = 2

so, a +(n-1)d =an

34+(n-1)*2 = 234

(n-1)2 = 234-34

n-1 = 200/2

n = 100+1

n =101

Now sum of the even no.

Sn = n/2( 2a+9n-1)d)
       
       = 101/2 (2*34 +100*2)
 
        = 101/2 * 268
 
          =101 *134
 
         = 13534
7 0
3 years ago
7 1
snow_tiger [21]

대답:

답은 다섯 번째입니다. 이 답변이 당신에게 맞기를 바랍니다.

7 0
3 years ago
Does anyone know how to graph this please help​
Anna71 [15]

Just like the Vertex Formula you do this:

y = 3(x - 4)³

This is where -H gives you the OPPOSITE terms of what they really are, and K gives you the NORMAL term, so just apply that to here. Whenever you are doing a phase shift, you put it in parentheses using the Vertex Formula, but giving the opposite term of what it really is:

Y = (X - H)² + K

Y = (X - H)³ + K

Now here is the graph. You see how I shifted it 4 units away from the origin?

So, find your roots [zeros (x-intercept)], plug in 0 for <em>y</em><em> </em>and solve for <em>x</em><em>.</em><em> </em>When you do this, you will get <em>4</em><em> </em><em>=</em><em> </em><em>x</em><em>.</em><em> </em>You could also look at the graph and can tell that the ONLY x-intercept is 4. So, either way, you will get the same result.

I am joyous to assist you anytime.

8 0
3 years ago
((16 - (4/2))^2) × 3 =
VARVARA [1.3K]

Answer:

588

Step-by-step explanation:

((16 - (4/2))^2) × 3      Simplify the inner parentheses

((16 - 2)^2) x 3     Solve inner parentheses again

((14)^2) x 3        Solve exponents

196 x 3      Multiply

588

7 0
3 years ago
At what distance along the central perpendicular axis of a uniformly charged disk of radius 0.600 m is the magnitude of the elec
Vesna [10]
Khrewrftw5elytg00<span>At what distance along the central perpendicular axis of a uniformly charged disk of radius 0.600 m is the magnitude of the electric field equal to one half the magnitude of th</span>
7 0
3 years ago
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