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3 years ago

What is the value of y where the two lines are equal?

Mathematics

2 answers:

Novosadov [1.4K]3 years ago

6 0

Answer:

y = - 1

Step-by-step explanation:

The 2 lines are equal at the point of intersection

The point of intersection is (2, - 1 ) with y = - 1

Stells [14]3 years ago

3 0

Answer:

y = -1

Step-by-step explanation:

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Match each value with its formula for ABC.

MariettaO [177]

The solution to the question is:

c is 6 = $\sqrt{a^{2} + b^{2} -2abcosC }$

b is 5 = $\sqrt{a^{2} + c^{2} -2accosB }$

cosB is 2 = $\frac{a^{2} + c^{2} - b^{2} }{2ac}$

a is 4 = $\sqrt{b^{2} + c^{2} -2bccosA }$

cosA is 3 = $\frac{b^{2} + c^{2} -a^{2} }{2bc}$

cosC is 1 = $\frac{b^{2} + a^{2} - c^{2} }{2ab}$

<h3>What is cosine rule?</h3>

it is used to relate the three sides of a triangle with the angle facing one of its sides.

The square of the side facing the included angle is equal to the some of the squares of the other sides and the product of twice the other two sides and the cosine of the included angle.

Analysis:

If c is the side facing the included angle C, then

$c^{2}$ = $a^{2}$ + $b^{2}$ -2ab cos C-----------------1

then c = $\sqrt{a^{2} + b^{2} -2abcosC }$

if b is the side facing the included angle B, then

$b^{2}$ = $a^{2}$ + $c^{2}$ -2accosB-----------------2

b = $\sqrt{a^{2} + c^{2} -2accosB }$

from equation 2, make cosB the subject of equation

2ac cosB = $a^{2}$ + $c^{2}$ - $b^{2}$

cosB = $\frac{a^{2} + c^{2} - b^{2} }{2ac}$

if a is the side facing the included angle A, then

$a^{2}$ = $b^{2}$ + $c^{2}$ -2bccosA--------------------3

a = $\sqrt{b^{2} + c^{2} -2bccosA }$

from equation 3, making cosA subject of the equation

2bcosA = $b^{2}$ + $c^{2}$ - $a^{2}$

cosA = $\frac{b^{2} + c^{2} -a^{2} }{2bc}$

from equation 1, making cos C the subject

2abcosC = $b^{2}$ + $a^{2}$ - $c^{2}$

cos C = $\frac{b^{2} + a^{2} - c^{2} }{2ab}$

In conclusion,

c is 6 = $\sqrt{a^{2} + b^{2} -2abcosC }$

b is 5 = $\sqrt{a^{2} + c^{2} -2accosB }$

cosB is 2 = $\frac{a^{2} + c^{2} - b^{2} }{2ac}$

a is 4 = $\sqrt{b^{2} + c^{2} -2bccosA }$

cosA is 3 = $\frac{b^{2} + c^{2} -a^{2} }{2bc}$

cosC is 1 = $\frac{b^{2} + a^{2} - c^{2} }{2ab}$

Learn more about cosine rule: brainly.com/question/4372174

$SPJ1

4 0

2 years ago

A scientist wants to study the average lifespan of a population of 1000 glow worms. He records the lifespan of a random selectio

scoray [572]

75 cuz max was gay really real happy

5 0

3 years ago

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Find the value of "x" in x² -2 = 47<br><br>Thanks :)

Dennis_Churaev [7]

$~~~~~x^2 -2 = 47\\\\\implies x^2 = 47 +2 \\\\\implies x^2 = 49\\\\\implies x = \pm\sqrt{49}\\\\\implies x = \pm 7\\\\\text{Hence, }~ x = 7,~~ x = -7$

7 0

2 years ago

Pls give all numbers

Bess [88]

Turkey dinner has to be zero as 0/? = 0 and it would be undefined if it was ?/0

Dinner plate would be 0 as ? * 0 * ? = 0

Radish is ?^2 cake as solving for radish will get that

Cake will be 4 as turkey is 0

Since cake is 4, radish is 16

Let’s plug them in to figure it out

0 / 4 = 0 ✅
16 * 0 * 4 = 0 ✅
4 = 16 / 4 ✅
4 / 4 = 0 + 1 ✅
0 + 16 * 4 = 64

Turkey = 0
Cake = 4
Radish = 16
Dinner plate = 0
? = 64

7 0

3 years ago

Pls answer this!!!!!!

jeka94

Answer:

Yes, because the total will be 51.50.

Step-by-step explanation:

3.75x3+6.50x4+14.25=51.50

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3 years ago

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What is the value of **y** where the two lines are equal?

What is the value of y where the two lines are equal?