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3 years ago

I have to solve for X?

Mathematics

1 answer:

VashaNatasha [74]3 years ago

4 0

yes

95+97 =192

192+x=180

x= -12

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PLEASE HELP DUE IN 20

Alekssandra [29.7K]

I HOPE IT WILL HELP YOU.

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3 years ago

A quadrilateral can be constructed with four obtuse angles. True False

nignag [31]

Yes it is true for example like a parrelogram that has 2 obtuse angels so which means it is true

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2 years ago

Choose which function is represented by the graph

Viefleur [7K]

Given:

The graph of a function.

To find:

The function.

Solution:

From the given graph, it is clear that the graph intersect the x-axis at x=-4, -2, 1. It means -4, -2 and 1 are zeros of the given function graph.

If c is a zero of a function f(x), then (x-c) is a factor of f(x).

Using the above definition, we conclude that (x+4), (x+2) and (x-1) are the factors of given function. So,

$f(x)=(x+4)(x+2)(x-1)$

$f(x)=(x-1)(x+2)(x+4)$

Therefore, the correct option is A.

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3 years ago

During optimal conditions, the rate of change of the population of a certain organism is proportional to the population at time

Lana71 [14]

Answer:

The population is of 500 after 10.22 hours.

Step-by-step explanation:

The rate of change of the population of a certain organism is proportional to the population at time t, in hours.

This means that the population can be modeled by the following differential equation:

$\frac{dP}{dt} = Pr$

In which r is the growth rate.

Solving by separation of variables, then integrating both sides, we have that:

$\frac{dP}{P} = r dt$

$\int \frac{dP}{P} = \int r dt$

$\ln{P} = rt + K$

Applying the exponential to both sides:

$P(t) = Ke^{rt}$

In which K is the initial population.

At time t = 0 hours, the population is 300.

This means that K = 300. So

$P(t) = 300e^{rt}$

At time t = 24 hours, the population is 1000.

This means that P(24) = 1000. We use this to find the growth rate. So

$P(t) = 300e^{rt}$

$1000 = 300e^{24r}$

$e^{24r} = \frac{1000}{300}$

$e^{24r} = \frac{10}{3}$

$\ln{e^{24r}} = \ln{\frac{10}{3}}$

$24r = \ln{\frac{10}{3}}$

$r = \frac{\ln{\frac{10}{3}}}{24}$

$r = 0.05$

$P(t) = 300e^{0.05t}$

At what time t is the population 500?

This is t for which P(t) = 500. So

$P(t) = 300e^{0.05t}$

$500 = 300e^{0.05t}$

$e^{0.05t} = \frac{500}{300}$

$e^{0.05t} = \frac{5}{3}$

$\ln{e^{0.05t}} = \ln{\frac{5}{3}}$

$0.05t = \ln{\frac{5}{3}}$

$t = \frac{\ln{\frac{5}{3}}}{0.05}$

$t = 10.22$

The population is of 500 after 10.22 hours.

7 0

2 years ago

Y = 4x - 6

Studentka2010 [4]

Answer:

B) 2x - 12x - 18 = 8

Step-by-step explanation:

2x - 3y = 8

If y = 4x - 6, then substitute and solve:

2x - 3(4x - 6) = 8

2x - 12x - 18 = 8

10x - 18 = 8

10x = 8 + 18

10x = 26

x = 26/10

x = 2.6

y = 4(2.6) - 6

y = 10.4 - 6

y = 4.4

8 0

3 years ago