Answer:
Step-by-step explanation:
You are to make 5 assemblies.
Each assembly requires the use of 1 Type A bolt.
To make the 5 assemblies, you need 5 Type A bolts.
The container of bolts has a total of 60 bolts.
The focus - Type A bolts - is 20 out of this 60.
The probability of obtaining a Type A bolt at all, is 20/60, which is = 1/3
(A) What is the probability of taking the exact number of Type A bolts you need for your 5 assemblies, if you randomly take 10 bolts from the container?
- The exact number of Type A bolts you need for the 5 assemblies is 5
1/3 × 5/10 = 5/30 = 1/6 = 0.167
(B) What is the probability of taking/having less than 5 Type A bolts out of the randomly selected 10 bolts? The solution is to sum up the following:
1/3 × 4/10 = 0.133
1/3 × 3/10 = 0.1
1/3 × 2/10 = 0.067
1/3 × 1/10 = 0.033
1/3 × 0/10 = 0
TOTAL = 0.333
18sqrt(15)
This has to be at least 20 characters long so yeaaaa
Answer:
The value of given expression = - 5mx
Step-by-step explanation:
Given expression;
10xm - 8mx + 6xm - 13xm
Find:
The value of given expression
Computation:
⇒ 10xm - 8mx + 6xm - 13xm
Step 1 ;
Rearrange expression;
⇒ 10mx - 8mx + 6mx - 13mx
Step 2 ;
Adding all terms
⇒ 10mx + 6mx - 8mx - 13mx
Step 3 :
Subtract term
⇒ 16mx - 21mx
⇒ -5mx
The value of given expression = - 5mx
X is equal to 2. The steps are listed below :)
Answer:
2
Step-by-step explanation:
5-3=2 it's simple really
