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3 years ago

7

Find Arc PRPlease help and give explanation

1 answer:

garri49 [273]3 years ago

8 0

Arc PR is 156 degrees. Since both angles are are making the forming arc they should be congruent. You can put (5x+23)=(9x-21) which is x=11.
Then you plug in 11 into your equation; 5(11)+23=78.
Since the vertex is on the outside of the circle then the arc is forms is 2 times the value of the angle.
78(2)=156

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Increase 140g by 12.5%

blsea [12.9K]

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

In a fraternity with 32 members, 18 take mathematics, 5 take both mathematics and literature, and 8 take neither mathematics nor

sukhopar [10]

Answer:

1 member took literature but not mathematics.

Step-by-step explanation:

We can draw a Venn diagram for the given question.

In a fraternity total number of members = 32

Number of members who took mathematics M = 18

Number of members who took both mathematics and literature (M∩L) = 5

And number of members who took neither mathematics nor literature = 8

Therefore, number of members who took literature but not mathematics

= 32 - [(18 + 5) + 8]

= 32 - [23 + 8]

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8 0

3 years ago

Read 2 more answers

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Alexxx [7]

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3 years ago

Simplify 4(2x^3y^4)^4/2(2x^2y^6)^3. Show your work. Please help ASAP!!

vovikov84 [41]

Answer:

The simplified expression to the given expression is $\frac{4x^6}{y^2}$

Therefore $\frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}=\frac{4x^6}{y^2}$

Step-by-step explanation:

Given fractional expression is $\frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}$

To simplify the given expression as below :

$\frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}$

$=\frac{2(2x^3y^4)^4}{(2x^2y^6)^3}$

$=\frac{2[(2)^4(x^3)^4(y^4)^4]}{(2)^3(x^2)^3(y^6)^3}$ ( using the property $(a^m)^n=a^{mn}$ )

$=\frac{2[(2)^4(x^{12})(y^{16})]}{(2)^3(x^6)(y^{18})}$

$=2[(2)^4(x^{12})(y^{16})](2)^{-3}(x^{-6})(y^{-18})$ ( ( using the property $a^m=\frac{1}{a^{-m}}$ )

$=2[2^{4-3}x^{12-6}y^{16-18}]$ ( using the property $a^m.a^n=a^{m+n}$ )

$=2[2^1x^6y^{-2}]$

$=\frac{4x^6}{y^2}$ ( using the property $a^m=\frac{1}{a^{-m}}$ )

Therefore the simplified expression is $\frac{4x^6}{y^2}$

Therefore $\frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}=\frac{4x^6}{y^2}$

5 0

3 years ago