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pashok25 [27]
3 years ago
8

Similarity transformations all preserve the shape of the figure? True of False

Mathematics
1 answer:
Irina-Kira [14]3 years ago
5 0
I'm not 100% but I'm pretty sure the answer is True
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Plz help ma :/<br><br><br> Helpppppppppppppppppppppp
Marizza181 [45]

Answer:

It is 432

Step-by-step explanation:

6 0
3 years ago
In the trapezoid ABCD ( AB ∥ CD ) point M∈ AD , so that AM:MD=3:5. Line l ∥ AB and going trough point M intersects diagonal AC a
geniusboy [140]

Answer:

BC:BN=8:3

Step-by-step explanation:

ABCD is a trapezoid and there is a point m which belongs to AD such that AM:MD=3:5.Line "l" parallel to AB intersects the diagonal AC at p and BD at N.

Now, we know that the parallel lines divide the transversal into the segments with equal ratio, therefore, BN:NC=AM:MD

But, BC= BN+NC

Therefore, BC:BN=(BN+NC):BN

⇒BC:BN=(3+5):3

⇒BC:BN=8:3


4 0
3 years ago
2 qurstions 100 points
Roman55 [17]

Answer:

1). 1.25 / 250 = .005M

.005 = 1 liter

2). (20)(.5) = 10M

have a good day, and be safe

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⊕ΘΞΠΤ⊕

∵∴∵∴∵∴∵∴∵

6 0
3 years ago
Solve the equation.<br><br> 89=x+13(7)
marissa [1.9K]
Answer is x=-2 hope that helps

5 0
3 years ago
Read 2 more answers
Assume that the national credit card interest rate is 12.83 percent. A study of 62 college students finds that their average int
meriva

Answer:

b)  95 percent confidence interval for this single-sample t test

[11.64, 16.36]

Step-by-step explanation:

Explanation:-

Given data  a study of 62 college students finds that their average interest rate is 14 percent with a standard deviation of 9.3 percent.

Sample size 'n' =62

sample mean x⁻ = 14  

sample standard deviation 'S' = 9.3

<u>95 percent confidence interval for this single-sample t test</u>

The values are (x^{-} - t_{0.05} \frac{S}{\sqrt{n} } ,x^{-}+t_{0.05}\frac{S}{\sqrt{n} })  the <u>95 percent confidence interval for the population mean  'μ'</u>

Degrees of freedom γ=n-1=62-1=61

t₀.₀₅ = 1.9996 at 61 degrees of freedom

(14 - 1.9996\frac{9.3}{\sqrt{62} } ,14+1.9996\frac{9.3}{\sqrt{62} })

(14-2.361 , 14 + 2.361)

[(11.64 , 16.36]

<u>Conclusion:-</u>

95 percent confidence interval for this single-sample t test

[11.64, 16.36]

<u></u>

6 0
3 years ago
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