Answer:
2.54 seconds
Step-by-step explanation:
We can use the following equation to model the vertical position of the ball:
S = So + Vo*t + a*t^2/2
Where S is the final position, So is the inicial position, Vo is the inicial speed, a is the acceleration and t is the time.
Then, using S = 2.5, So = 0.4, Vo = 14 and a = -9.8 m/s2, we have that:
2.5 = 0.4 + 14*t - 4.9t^2
4.9t^2 - 14t + 2.1 = 0
Solving this quadratic equation, we have that t1 = 2.6983 s and t2 = 0.1588 s.
Between these times, the ball will be higher than 2.5 m, so the amount of time the ball will be higher than 2.5 m is:
t1 - t2 = 2.6983 - 0.1588 = 2.54 seconds
A/4 = 8/16
cross multiply
(16)(A) = (8)(4)
16A = 32
A = 32/16
A = 2
9514 1404 393
Answer:
sin(θ) ≈ -0.92
cos(θ) ≈ 0.38
tan(θ) = -2.40
Step-by-step explanation:
Let r represent the distance of the point from the origin. The Pythagorean theorem tells us ...
r² = (5)² + (-12)²
r² = 169
r = √169 = 13
The trig relations for a point on the terminal ray are ...
(x, y) = (r·cos(θ), r·sin(θ))
Then ...
sin(θ) = y/r = -12/13 ≈ -0.92
cos(θ) = x/r = 5/13 ≈ 0.38
tan(θ) = y/x = -12/5 = -2.40
Answer:
C 101,250
Step-by-step explanation:
divide 45 by 3 its 15 so do 15x2 and 15x5 and multiply those together to find the volume
