3 years ago

Similarity transformations all preserve the shape of the figure? True of False

1 answer:

5 0

I'm not 100% but I'm pretty sure the answer is True

You might be interested in

bagirrra123 [75]

Answer:

Step-by-step explanation:

your welcome

5 0

3 years ago

Vesnalui [34]

Aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

5 0

3 years ago

Tomtit [17]

Answer:

Verified

Step-by-step explanation:

Use $\tan{x}=\frac{\sin{x}}{\cos{x}}$ , $\sin^2{x}+\cos^2{x}=1$ and $\sec{x}=\frac{1}{\cos{x}}$

LHS= $\tan^2{x}+1=\frac{\sin^2{x}}{\cos^2{x}} + 1=\frac{\sin^2{x}+\cos^2{x}}{\cos^2{x}}=\frac{1}{\cos^2{x}}=\sec^2{x}$ =RHS

5 0

2 years ago

omeli [17]

Answer:

- (5/22)

Step-by-step explanation:

(12-2x+8)/3 = (6x + 15)/2

(20 - 2x)/3 = ( 6x + 15)/2

Now cross multiplication

40 - 4x = 18x + 45

-18x - 4x = 45- 40

- 22x = 5

x = - ( 5/22)

3 0

3 years ago

jenyasd209 [6]

A is commutative property
B is associative property
Explanation:

5 0

3 years ago