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Fofino [41]
3 years ago
7

2. True help will be greatly appreciated, tricks or games will be reported; no links or websites or pdfs. Thanks!

Mathematics
2 answers:
oksian1 [2.3K]3 years ago
5 0

Answer:

7. y=1/4x

8. 3 3/4

Hope this helps!

Step-by-step explanation:

frutty [35]3 years ago
3 0
The correct answer is D y=7/4x
The way you find out the answer is you start at the orgin (0,0) then count up to 14 and go 8 to the right and you will hit the line . Remember to find slope Rise over Run. Then slope would be 14/8 then
reduce to 7/4.

The next answer is A 3/20
Multiply the two fractions
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Please solve the attached problem and chose from the answers below.
DanielleElmas [232]

Answer:

C

Step-by-step explanation:

\frac{5}{4t}-\frac{t+4}{10t^2}=\frac{5\left(10t^2\right)-4t\left(t+4\right)}{40t^3}=\frac{2t\left(25t-2\left(t+4\right)\right)}{40t^3}=\frac{\left(25t-2t-8\right)}{20t^2}=\frac{23t-8}{20t^2}

4 0
2 years ago
Read 2 more answers
the Hamilton eighth-grader took a trip to Myrtle beach. They drove a speed of 60 miles per hour. The trip was 570 miles. Write a
Simora [160]

Answer:

9.5

Step-by-step explanation:

60h = 570

Divide 60 by both sides

h = 9.5

3 0
2 years ago
WHICH INQUALITY IS EQUAL TO -1 > M+4
PIT_PIT [208]

Answer:

m<−5

Step-by-step explanation:

Step 1: Flip the equation.

m+4<−1

Step 2: Subtract 4 from both sides.

m+4−4<−1−4

m<−5

Hope this helped <3

5 0
3 years ago
Find the distance between the points (-7, -6) and (-3, 0).
FrozenT [24]

Answer:

7.21 unit

Step-by-step explanation:

distance= √[(-7+3)^2 + (-6-0)^2]

= 7.21 unit

5 0
3 years ago
Rationalize the denominator of 4/14 root 2?
Katarina [22]

First of all, you can simplify the 4 at the numerator and the 14 at the denominator (they're both multiple of 2):

\dfrac{4}{14\sqrt{2}} = \dfrac{2\cdot 2}{2\cdot 7\cdot\sqrt{2}} = \dfrac{2}{7\sqrt{2}}

Now, rationalize a denominator means that you have to get rid of the square root, in order to have an integer denominator.

To do so, remember that you can always multiply any number by 1 without changing its value, and you can always think of 1 as a fraction where numerator and denominator are equal:

\dfrac{2}{7\sqrt{2}} = \dfrac{2}{7\sqrt{2}}\cdot 1 = \dfrac{2}{7\sqrt{2}} \cdot \dfrac{\sqrt{2}}{\sqrt{2}} = \dfrac{2\sqrt{2}}{7\cdot 2} = \dfrac{\sqrt{2}}{7}

5 0
3 years ago
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