Step-by-step explanation:
Let
x
be the kg of coffee of brand A in the mix and
y
be the kg of coffee of brand B in the mix.
The total kg must be
50
.
x
+
y
=
50
The cost per kg of the mix must br
$
7.20
. For this, the total cost of the mix will be
6
x
+
8
y
, so the total cost per kg of the mix will be
6
x
+
8
y
50
.
6
x
+
8
y
50
=
7.20
Now that we have our two equations, we can solve.
6
x
+
8
y
=
7.20
⋅
50
6
x
+
8
y
=
360
From the first equation, we can multiply both sides by
6
to get:
6
x
+
6
y
=
300
Subtracting, we get:
2
y
=
60
y
=
30
Thus, we need
30
kg of brand B in our mix. This means that
50
−
30
=
20
kg will be of brand A.
I'm not sure what your table and graph look like but they might both represent the relationship between numbers, like the common difference (+5 ect) They could also both represent positive growth or negative growth depending on how the graph and table look.
Hope this helps!
When you add a zero to the problem, it shows you are now multiplying in the double-digits. Let's say you are multiplying 12x12. First you cover up the one then multiply them. Then cover up the two and you have 10. When you multiply them, it ends in a zero. Don't think of it as adding a zero but adding to products.
3.5h+10=5.25h-11
21=1.75h
12=h
3.5(12)+10=5.25(12)-11
52=52
<span><span>4−3</span>−<span><span>(2)</span><span>(<span>−6</span>)</span></span></span><span>=<span>1−<span><span>(2)</span><span>(<span>−6</span>)</span></span></span></span><span>=<span>1−<span>(<span>−12</span>)</span></span></span><span>=<span>13</span></span>
