Answer:490pi
Step-by-step explanation:just trust me
Answer:
omg
I
1. 3×3×3×3 = 81
2. 2²a³
3. (-5)³ (-5×-5×-5) = -125
4. 1
5. a^m-n
II
1. 1.6807× 10⁴
2. (7×7×7) × (2×2×2×2×2×2) = 21952
3. 32²
4. 2187
5. 803025
Answer:
lateral area = 2320 m²
Step-by-step explanation:
The question wants us to calculate the lateral area of a square base pyramid. The square base pyramid has a side of 40 meters.The height is 21 meters.
Half of the square base is 40/2 = 20 meters . With the height it forms a right angle triangle. The hypotenuse side is the slant height of the pyramid.
Using Pythagoras's theorem
c² = a² + b²
c² = 20² + 21²
c² = 400 + 441
c² = 841
square root both sides
c = √841
c = 29 meters
The slant height of the pyramid is 29 meters.
The pyramid has four sided triangle. The lateral area is 4 multiply by the area of one triangle.
area of triangle = 1/2 × base × height
base = 40 meters
height = 29 meters
area = 1/2 × 40 × 29
area = 580
area of one triangle = 580 m²
Lateral area = 4(580)
lateral area = 2320 m²
The answer is 90
20%of 99=18
Answer:
im assuming you need the volume of this container:
