The equation for the axis of symmetry is. :c x=2
Below is the solution, I hope it helps.
<span>i) tan(70) - tan(50) = tan(60 + 10) - tan(60 - 10)
= {tan(60) + tan(10)}/{1 - tan(60)*tan(10)} - {tan(60) - tan(10)}/{1 + tan(10)*tan(60)}
ii) Taking LCM & simplifying with applying tan(60) = √3, the above simplifies to:
= 8*tan(10)/{1 - 3*tan²(10)}
iii) So tan(70) - tan(50) + tan(10) = 8*tan(10)/{1 - 3*tan²(10)} + tan(10)
= [8*tan(10) + tan(10) - 3*tan³(10)]/{1 - 3*tan²(10)}
= [9*tan(10) - 3*tan³(10)]/{1 - 3*tan²(10)}
= 3 [3*tan(10) - tan³(10)]/{1 - 3*tan²(10)}
= 3*tan(30) = 3*(1/√3) = √3 [Proved]
[Since tan(3A) = {3*tan(A) - tan³(A)}/{1 - 3*tan²(A)},
{3*tan(10) - tan³(10)}/{1 - 3*tan²(10)} = tan(3*10) = tan(30)]</span>
Answer:
no
Step-by-step explanation:
Answer:
The circumference is 37.7 mm Hope this helped! Have a great day!! :)
Step-by-step explanation:
Hey there!
In order to solve this, all you need to do is cancel out terms until you have n on one side of the equal sign and everything else on the other side.
14n + q = rt – 4n (add 4n to both sides to combine 4n and 14n)
18n + q = rt (subtract q from both sides)
18n = rt – q (divide both sides by 18)
n = (rt – q) ÷ 18
Hope this helped you out! :-)
