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Ludmilka [50]
2 years ago
10

Help, please!!! 7th Grade math!

Mathematics
2 answers:
BigorU [14]2 years ago
3 0

Answer:-3

Step-by-step explanation:

4^2=16, 1^3=1, (-3)^2=9

so

16-1+3=18/(3-9)

so 18/-6= -3

Mila [183]2 years ago
3 0

Answer:

-3

Step-by-step explanation:

solve for 4^{2} -1x^{3} + 3

Use PEMDAS (parentheses, exponents, multiplication, division, addition, subtraction)

16-1^3+3

16-1+3

18

Solve for 3-(-3)^{2}

Use PEMDAS (parentheses, exponents, multiplication, division, addition, subtraction)

3-9

-6

Plug your answer back in

\frac{18}{-6}

Divide

-3

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3 years ago
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Why is it important to know the different properties of three-dimensional figures
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4 0
3 years ago
Find the degree measure of each angle in the triangle
Karo-lina-s [1.5K]

Answer:

∠L = 43°

∠M = 121°

∠N = 16°

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<u>Start by setting all sides equal to 180</u>

3x - 5 + 7x + 9 + x = 180

<u>Add like terms</u>

11x + 4 = 180

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11x + 4 = 180

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8 0
2 years ago
Consider the equation below.
Korvikt [17]

Answer:

Equation in square form:

y=3(x+5)^2-4

Extreme value:

(h,k)=(-5,-4)

Step-by-step explanation:

We are given

y=3x^2+30x+71

we can complete square

y=3(x^2+10x)+71

we can use formula

a^2+2ab+b^2=(a+b)^2

y=3(x^2+2\times x\times 5)+71

now, we can add and subtract 5^2

y=3(x^2+2\times x\times 5+5^2-5^2)+71

y=3(x^2+2\times x\times 5+5^2)-3\times 5^2+71

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So, we get equation as

y=3(x+5)^2-4

Extreme values:

we know that this parabola

and vertex of parabola always at extreme values

so, we can compare it with

y=a(x-h)^2+k

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vertex=(h,k)

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y=3(x+5)^2-4

we get

h=-5

k=-4

so, extreme value of this equation is

(h,k)=(-5,-4)

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3 years ago
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