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3241004551 [841]
3 years ago
9

Activity 2 Compute for the following: Speed; Distance, Time

Mathematics
1 answer:
zhuklara [117]3 years ago
3 0

Answer:

1. 50 km/h

2. 900 km/h

3. 3 hours

Step-by-step explanation:

1. The distance the car travels, Δd = 300 km

For how long it takes the car to travel the 300 km, Δt = 6 hours

Average speed, \overline v, is given as follows;

\overline v  = \dfrac{The \ total \ distance }{The  \ total \ time \ it \ takes } = \dfrac{\Delta d}{\Delta t},

\therefore \overline v = \dfrac{300 \ km}{6 \ hours} = 50 \ \dfrac{km}{hour}

The average speed of the car, \overline v = 50 km/h

2. The distance the jet plane flies, d = 8,100 km

For how long it takes the the jet plane to fly the 8,100 km, t = 9 hours

The speed, v, of the jet plane is given as follows;

Speed, \ v = \dfrac{Distance}{Time} = \dfrac{d}{t}

v = \dfrac{The\ distance \ the \ jet plane \ flies}{The   \ time \ it \ takes \ to \ fly \ thart \ distance } = \dfrac{d}{t },

\therefore v = \dfrac{8,100 \ km}{9 \ hours} = 900 \ \dfrac{km}{hour}

The speed of the jet plane, v = 900 km/h

3. The speed of the storm, v = 20 km/h

The distance of the storm from the house, d = 60 km

The time 't' it takes the storm to reach the house is given as follows;

Speed, \ v =  \dfrac{d}{t}

Therefore, by cross multiplying and dividing by 'v', we get;

Time, \ t =  \dfrac{d}{v}

Plugging in the known values of 'd' and 'v' gives;

Time, \ t =  \dfrac{60 \ km}{20 \ \dfrac{km}{hour} } = 3 \ km \times  \dfrac{hour}{km} = 3 \ hours

The time it takes the storm to reach the house, t = 3 hours.

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Answer:

a) The mean number is 745 and the standard deviation is 25.18.

b) 896 deaths is a significantly high number, which means that there is cause for concern.

Step-by-step explanation:

For each death, there are only two possible outcomes. Either it is attributable to myocardial infarctions, or it is not. The probability of a death being attributable to myocardial infarctions is independent of other deaths. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

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The expected value of the binomial distribution is:

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The standard deviation of the binomial distribution is:

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A value X is significantly high is:

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In this problem:

p = 0.149, n = 5000

a. Find the mean and standard deviation for the number of such deaths that will occur in typical region with 5000 deaths.

E(X) = np = 5000*0.149 = 745

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{5000*0.149*0.851} = 25.18

The mean number is 745 and the standard deviation is 25.18.

b. In one region, 5000 death certificates are examined, and it is found that 896 deaths were attributable to myocardial infarction. Is there cause for concern? Why or why not?

Is 896 a significantly high number?

E(X) + 2\sqrt{V(X)} = 745 + 2*25.18 = 795.36

895 > 795.36

896 deaths is a significantly high number, which means that there is cause for concern.

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