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mart [117]
2 years ago
5

8.

Mathematics
1 answer:
Semenov [28]2 years ago
8 0

Answer:

= 3^9

Step-by-step explanation:

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[] For the last two I think I am missing some information as I do not have any numbers and know where they got 85 from.

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

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2 years ago
I need help plz <br><br> .........<br> .......<br> .......
Anarel [89]

Answer:

v=-60

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A scientist is experimenting with bacteria in his laboratory He starts out with 3 bacteria
never [62]
X+1 to the second power
6 0
3 years ago
Class A has 15 pupils and class B has 29 pupils.
Vaselesa [24]

The mean score (rounded to 2 DP) in the Math's test for class B is 86.86.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Class A has 15 pupils and class B has 29 pupils. The mean score for class A is 55. Hence:

Mean score of A = (sum of all scores) / 15

55 =  (sum of all scores) / 15

sum of all scores in A = 825

The mean score for both classes is 76. Hence:

[(sum of all scores in A) + (sum of all scores in B)]/(total number of pupils) = mean score of both classes

[825 + (sum of all scores in B)]/(15 + 29) = 76

sum of all scores in B = 2519

Mean score of B = (2519) / 29 = 86.86

The mean score (rounded to 2 DP) in the Math's test for class B is 86.86.

Find out more on equation at: brainly.com/question/13763238

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6 0
1 year ago
A survey of 46 college athletes found that 24 played volleyball, while 22 played basketball. a) If we pick one athlete survey pa
PSYCHO15rus [73]

Answer:

A) \dfrac{11}{23}

B) \dfrac{88}{345}

Step-by-step explanation:

A survey of 46 college athletes found that

  • 24 played volleyball,
  • 22 played basketball.

A) If we pick one athlete survey participant at random,  the probability they play basketball is

P_1=\dfrac{22}{46}=\dfrac{11}{23}

B) If we pick 2 athletes at random (without replacement),

  • the probability we get one volleyball player is \dfrac{24}{46}=\dfrac{12}{23};
  • the probability we get another basketball player is \dfrac{22}{45} (only 45 athletes left).

Thus, the probability we get one volleyball player and one basketball player is

P_2=\dfrac{12}{23}\cdot \dfrac{22}{45}=\dfrac{88}{345}

5 0
3 years ago
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