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mart [117]
2 years ago
5

8.

Mathematics
1 answer:
Semenov [28]2 years ago
8 0

Answer:

= 3^9

Step-by-step explanation:

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What is .25 written in the simplest fraction form
Alekssandra [29.7K]
1/4 is .25 as a fraction
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3 years ago
Which linear equations does the graph show the solution to? Select all that apply. y = 2x + 13 y = –x – 2 y = 3x – 5 y = negativ
salantis [7]

Answer:

y = 2x + 13

y = –x – 2

Step-by-step explanation:

The options are:

y = 2x + 13

y = -x - 2

y = 3x - 5

y= -(1/2)x + 6

y = -2x - 2

The graph is shown in the figure attached. There, point (-5, 3) is shown. Replacing it into the equations we get:

y = 2(-5) + 13  = 3    (so, it is a solution)

y = -(-5) - 2 = 3     (so, it is a solution)

y = 3(-5) - 5  = -20 ≠ 3   (so, it isn't a solution)

y= -(1/2)(-5) + 6  = 8.5 ≠ 3     (so, it isn't a solution)

y = -2(-5) - 2 = 8 ≠ 3     (so, it isn't a solution)

6 0
3 years ago
Read 2 more answers
A taxi costs $1.25 for the first mile and $0.75 for each additional mile. Yohana spent $10.25 to take a taxi to the airport. If
denis-greek [22]
1.25+.75m+10.25  and 13 miles
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3 years ago
The Wild Dogs and the Rattlers also have membership programs. The Wild Dogs' initial fee is $20 and single game tickets are $1.5
tester [92]

Answer:

The first Answer is

 x-min = 0, x-max = 20

What is the best window range of y-values to find the solution?

y-min = 20 , y-max = 40

What is the solution?

8 games will cost $32

7 0
3 years ago
Two cards are selected from a standard deck of 52 playing cards. the first is replaced before the second card is selected. find
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<span>The correct answer is
</span>  Find the probability of selecting a diamond and then selecting a queen.

 standard deck of 52 playing cards

<span>hearts: 2, 3, 4, 5, 6, 7, 8, 9, 10, j, q, k, A---- > 13 cards</span>

<span>clubs: 2, 3, 4, 5, 6, 7, 8, 9, 10, j, q, k, A---- > 13 cards</span>

<span>spades: 2, 3, 4, 5, 6, 7, 8, 9, 10, j, q, k, A---- > 13 cards</span>

<span>diamonds: 2, 3, 4, 5, 6, 7, 8, 9, 10, j, q, k, A---- > 13 cards</span>

 a)  The probability of selecting a diamond is 13/52

<span>b)  </span>The probability of selecting a queen is 4/52

<span>c)   </span>The probability of selecting a diamond and then selecting a queen is

(13/52)*(4/52)=0.0192------------->1.92%

6 0
3 years ago
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