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denis-greek [22]
3 years ago
10

Is 3/2 an allowable probability? Explain.

Mathematics
1 answer:
nadezda [96]3 years ago
7 0
No, probably is on a scale between 0 and 1. Anything beyond those numbers is mathematically impossible. Since 3/2 = 1.5, it is not valid
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Given the domain (-2,2,4) what is the range for the relation 3x-y=3
Bumek [7]

Answer:

Given the domain, the range for 3x-y = 3 is {-9, 6, 9}

Step-by-step explanation:

First you have to put the relation in terms of y ⇒ 3x - y = 3⇒ 3x -3 = y

⇒ y = 3x - 3.

Then you replace the values indicated by the domain to find their "y" values (the ones that constitute the range).

f(-2) = -9

f(2) = 6

f(4) = 9.

Finally, the range for the given domain is {-9, 6, 9}

3 0
3 years ago
What is the measure of the central angle of a circle with radius 60 cm the intercepts a 15 pi centimeters arc
alekssr [168]

The measure of the central angle of a circle is 45⁰

<h3>What is Angle?</h3>

A figure which is formed by two rays or lines that shares a common endpoint is called an angle.

Here,

Theta (angle) θ = arc length / radius

θ = 15 π / 60 cm

θ =  0.79 radians

Convert to degrees

θ = 0.79 radians = 0.79 X 180/ π

                     = 0.79 X 180/ 3.14

                     = 45⁰

Thus, the measure of the central angle of a circle is 45⁰.

Learn more about Angle from:

brainly.com/question/7116550

#SPJ1

6 0
2 years ago
Quadrilateral ABCD is a square with diagonals that intersect at point E. Find angle ADB. A. 11.25º B. 22.5º C. 45º D. 90º
never [62]

IT WOULD BE "D" I BELIEVE

HOPE IM RIGHT AND THIS HELPS


7 0
3 years ago
Read 2 more answers
2/3 + w = 3/2 what is w
german

Answer:

0.8333

Step-by-step explanation:

2/3 + x

x + 2/3

x + 2/3 = 3/2

x + 2/3 - 3/2 = 0

2/3 - 3/2 = 4/6 - 9/6 = - 5/6

x - 5/6 = 0

use linear function

f(x) - ax + b

f(x) = x - 5/6

a = 1

b = - 5/6

x- 5/6= 0

x = 5/6

x = 0.8333

6 0
3 years ago
Solve the compound inequality 6b &lt; 42 or 4b + 12 &gt; 8
swat32

Answer:

b<7

Step-by-step explanation:

6b<42

42/6 = 7

b<7

3 0
4 years ago
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