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Valentin [98]
3 years ago
13

Whats 3 to the 2nd power times 3 to the 5th power in a single exponent

Mathematics
2 answers:
Nataly [62]3 years ago
7 0

Answer:

3 to the 7th power

Step-by-step explanation:

add the exponents

bezimeni [28]3 years ago
3 0

Answer:

3^7

Step-by-step explanation:

3^2 * 3^5 = 3^(2+5) = 3^7

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Answer:

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5 0
3 years ago
An open metal tank of square base has a volume of 123 m^3
snow_lady [41]

Answer:

  a) h = 123/x^2

  b) S = x^2 +492/x

  c) x ≈ 6.27

  d) S'' = 6; area is a minimum (Y)

  e) Amin ≈ 117.78 m²

Step-by-step explanation:

a) The volume is given by ...

  V = Bh

where B is the area of the base, x^2, and h is the height. Filling in the given volume, and solving for the height, we get:

  123 = x^2·h

  h = 123/x^2

__

b) The surface area is the sum of the area of the base (x^2) and the lateral area, which is the product of the height and the perimeter of the base.

S=x^2+Ph=x^2+(4x)\dfrac{123}{x^2}\\\\S=x^2+\dfrac{492}{x}

__

c) The derivative of the area with respect to x is ...

S'=2x-\dfrac{492}{x^2}

When this is zero, area is at an extreme.

0=2x -\dfrac{492}{x^2}\\\\0=x^3-246\\\\x=\sqrt[3]{246}\approx 6.26583

__

d) The second derivative is ...

S''=2+\dfrac{2\cdot 492}{x^3}=2+\dfrac{2\cdot 492}{246}=6

This is positive, so the value of x found represents a minimum of the area function.

__

e) The minimum area is ...

S=x^2+\dfrac{2\cdot 246}{x}=(246^{\frac{1}{3}})^2+2\dfrac{246}{246^{\frac{1}{3}}}=3\cdot 246^{\frac{2}{3}}\approx 117.78

The minimum area of metal used is about 117.78 m².

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2 years ago
Suppose that all of the points on the circular dartboard shown are equally likely to be hit by a dart. If the radius of the shad
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This must double your chances so if i round the nearest whole number would be 8 any questions?
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3 years ago
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Vladimir79 [104]
He could be 40321 years old.
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I got this number by doing (2*3*4*5*6*7*8) + 1
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Please answer number 1 and 2.
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1, a.) The two specific conjectures are in the first image.

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