-7z - 7 ≤ -5z + 5 need help sloving

Mathematics

2 answers:

V125BC [204]3 years ago

7 0

-7z - 7 ≤ -5z + 5

- 7 - 5 ≤ -5z + 7z
-12 ≤ 2z
-12/2 ≤ z
-6 ≤ z or z>= -6

Lostsunrise [7]3 years ago

6 0

This is an inequality problem. The way to solve this is to treat the inequality sign (<, >, etc) like an equal sign (=).

-7z - 7 = -5z + 5

first, you get rid of the constants (the numbers that don't have variables with them)
the way to do that is to perform reverse operations (when there is a negative, add. when positive, subtract. same for multiplying and dividing)

-7z - 7 = -5z + 5
+ 7    + 7
------------------------
-7z = -5z + 12

the sevens are cancelled out because of the + and the - on both of them, and 5+7 is 12.
now, for the coefficients. you do the same process.

-7z - 7 = -5z + 5
+ 7    + 7
------------------------
  -7z = -5z + 12
+5z +5z
-------------------------
-2z = 12

now that you have combined all the alike terms, you divide until the variable is by itself. (/ is divide)

-7z - 7 = -5z + 5
+ 7    + 7
------------------------
  -7z = -5z + 12
+5z +5z
-------------------------
-2z = 12
/-2 /-2
-----------------------
z = -6

twelve divided by -2 is -6. so, z = -6.
now all you have to do is switch out the inequality sign: z < -6

You might be interested in

1.5.3 Quiz: Literal Equations and Formulas

sweet-ann [11.9K]

Answer:

c = F-32; 68-32 = 36°C.

Step-by-step explanation:

the real conversation equation is f = 9/5 C + 32. but for the sake of this problem we are ignoring the coefficient.

so it's 36°C

3 0

3 years ago

A man invests his savings in two accounts, one paying 6% and the other paying 10% simple interest per year. He puts twice as muc

Masteriza [31]

Let x represent amount invested in the higher-yielding account.

We have been given that a man puts twice as much in the lower-yielding account because it is less risky. So amount invested in the lower-yielding account would be $2x$ .