-7z - 7 ≤ -5z + 5 need help sloving
2 answers:
-7z - 7 ≤ -5z + 5 - 7 - 5 ≤ -5z + 7z -12 ≤ 2z -12/2 ≤ z -6 ≤ z or z>= -6
This is an inequality problem. The way to solve this is to treat the inequality sign (<, >, etc) like an equal sign (=). -7z - 7 = -5z + 5 first, you get rid of the constants (the numbers that don't have variables with them) the way to do that is to perform reverse operations (when there is a negative, add. when positive, subtract. same for multiplying and dividing) -7z - 7 = -5z + 5 + 7 + 7 ------------------------ -7z = -5z + 12 the sevens are cancelled out because of the + and the - on both of them, and 5+7 is 12. now, for the coefficients. you do the same process. -7z - 7 = -5z + 5 + 7 + 7 ------------------------ -7z = -5z + 12 +5z +5z ------------------------- -2z = 12 now that you have combined all the alike terms, you divide until the variable is by itself. (/ is divide) -7z - 7 = -5z + 5 + 7 + 7 ------------------------ -7z = -5z + 12 +5z +5z ------------------------- -2z = 12 /-2 /-2 ----------------------- z = -6 twelve divided by -2 is -6. so, z = -6. now all you have to do is switch out the inequality sign: z < -6
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