-7z - 7 ≤ -5z + 5 need help sloving

Mathematics

2 answers:

V125BC [204]3 years ago

7 0

-7z - 7 ≤ -5z + 5

- 7 - 5 ≤ -5z + 7z
-12 ≤ 2z
-12/2 ≤ z
-6 ≤ z or z>= -6

Lostsunrise [7]3 years ago

6 0

This is an inequality problem. The way to solve this is to treat the inequality sign (<, >, etc) like an equal sign (=).

-7z - 7 = -5z + 5

first, you get rid of the constants (the numbers that don't have variables with them)
the way to do that is to perform reverse operations (when there is a negative, add. when positive, subtract. same for multiplying and dividing)

-7z - 7 = -5z + 5
+ 7    + 7
------------------------
-7z = -5z + 12

the sevens are cancelled out because of the + and the - on both of them, and 5+7 is 12.
now, for the coefficients. you do the same process.

-7z - 7 = -5z + 5
+ 7    + 7
------------------------
  -7z = -5z + 12
+5z +5z
-------------------------
-2z = 12

now that you have combined all the alike terms, you divide until the variable is by itself. (/ is divide)

-7z - 7 = -5z + 5
+ 7    + 7
------------------------
  -7z = -5z + 12
+5z +5z
-------------------------
-2z = 12
/-2 /-2
-----------------------
z = -6

twelve divided by -2 is -6. so, z = -6.
now all you have to do is switch out the inequality sign: z < -6

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=================================================

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