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3 years ago

(3x²-21x-24)take out the highest common factor

Mathematics

2 answers:

Oduvanchick [21]3 years ago

7 0

3(x-8)(x+1)
i need characters sjushsjsbs lol

inessss [21]3 years ago

6 0

Answer:

x = 8 or x = -1 is the answer

Step-by-step explanation:

3x² - 21x -24

divide with 3

x² - 7x - 8

Factorizing,

x² + x - 8x - 8

x(x + 1) -8 (x + 1)

(x - 8) (x + 1)

x = 8,-1

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Consider a circle whose equation is x2 + y2 – 2x – 8 = 0. Which statements are true? Select three options. The radius of the cir

FromTheMoon [43]

The statements which are correct about the equation of circle $x^{2} +y^{2}-2x-8=0$ are 1) The radius of the circle is 3 units,2) The center of the circle lies on the x axis,5) The radius of this circle is the same the radius of the circle whose equation is $x^{2} +y^{2} =9$ .

Given the equation of circle be $x^{2} +y^{2}-2x-8=0$ .

We are required to find the appropriate statements related to the equation $x^{2} +y^{2}-2x-8=0$ .

$x^{2} +y^{2}-2x-8=0$ can be written as under:

$x^{2} +y^{2} -2x+1-9=0$

$x^{2} +1^{2}-2x+y^{2} -9=0$

$(x-1)^{2}+y^{2}$ -9=0

$(x-1)^{2} +y^{2} =9$

$(x-1)^{2}+y^{2} =3^{2}$

Equation of a circle usually in the form $x^{2} +y^{2} =a^{2}$ in which a is radius.

From the comparison of both the equations we get that radius is 3 units.

From the equation point will be (1,0). It is on the x axis.

Hence the statements which are correct about the equation of circle $x^{2} +y^{2}-2x-8=0$ are 1) The radius of the circle is 3 units,2) The center of the circle lies on the x axis,5) The radius of this circle is the same the radius of the circle whose equation is $x^{2} +y^{2} =9$ .

Learn more about radius at brainly.com/question/24375372

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1 year ago

What is the length of the hypotenuse of the triangle when x=14

astra-53 [7]

The length of the hypotenuse will be equal to H=122.25 when value of x=14.

<h3>What is pythagorean theorem?</h3>

Pythagorean theorem states that in the right angle triangle the hypotenuse square is equal the square of the sum of the other two sides.

It is given that:

Value of x=14

The perpendicular is =6x+5=6x14+5=89

The base is =6x=84

So by using the Pythagorean theorem:-

$H^2=P^2+B^2\\\\\\H^2=89^2+84^2\\\\\\H=\sqrt{89^2+84^2}\\\\\$