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g100num [7]
3 years ago
8

One third plus four sixths plus six eighteenths equals blank

Mathematics
2 answers:
ss7ja [257]3 years ago
7 0

Answer:

1 1/3

Step-by-step explanation:

hodyreva [135]3 years ago
4 0

Answer:

7/6

Step-by-step explanation:

1/3+4/8+6/18=7/6

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he lengths of a particular​ animal's pregnancies are approximately normally​ distributed, with mean muequals252 days and standar
Rashid [163]

Answer:

Step-by-step explanation:

Let X be the lengths of a particular​ animal's pregnancies

X is N(252, 20)

​(a) What proportion of pregnancies lasts more than 262 ​days? ​

P(X>262) = 0.3085

(b) What proportion of pregnancies lasts between 227 and 257 ​days?

P(227

​(c) What is the probability that a randomly selected pregnancy lasts no more than 237 ​days?

P(X<237) = 0.2266

​(d) A​ "very preterm" baby is one whose gestation period is less than 202 days. Are very preterm babies​ unusual?

P(X

Yes very unusual since probability is very near to 0.

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4 years ago
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Svetlanka [38]

Answer:

I've solved the answer on the attached paper

5 0
3 years ago
A ball is thrown into the air with an upward velocity of 48 ft/s. Its height h in feet after t seconds is given by the function
stiv31 [10]
The answer to this, your question is                                                                               h = -16t • 2 + 48t + 6
h = -32t + 48t + 6
h = 16t + 6     HOPE I HELPED IN A WAY!                                                                                                                                             ~Marcey<3
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3 years ago
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Help me with this question please. Due now
KengaRu [80]

Answer:

I don't know nahakan zhuaksnzbu mkauzgbs kiuhsbs s kiuhs

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Name Date 34bral Kuta Software - Infinite Algebra 2 Solving Absolute Value Equations Solve each equation. 1) 13x1=9 2) 1-3r1=9 R
vichka [17]
-5|3+4k|=-115

start by dividing both sided by -5

\frac{-5}{-5}|3+4k|=-\frac{115}{-5}|3+4k|=23

when we have an absolute we obtain two equations, one for the positive value and one for the negative value

\begin{gathered} 3+4k=23 \\ -(3+4k)=23 \end{gathered}

solve each of them

\begin{gathered} 3+4k=23 \\ 4k=23-3 \\ 4k=20 \\ k=\frac{20}{4}=5 \end{gathered}

for the second equation

\begin{gathered} -(3+4k)=23 \\ -3-4k=23 \\ -4k=23+3 \\ -4k=26 \\ k=-\frac{26}{4}=-6.5 \end{gathered}

the solutions for k are -6.5 and 5

4 0
1 year ago
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